Suppose a 20.0 g gold bar at 35.0°C absorbs 70.0 calories of heat energy. Given that the specific heat of gold is 0.0310 cal/g °

Answer:

The calculated density of the liquid is 1470.43 kg/m³.

Explanation:

Given:

Mass of the solid sphere (m) = 6.1 kg

Density of the metal = 2600 kg/m³

To find the volume of the liquid:

Volume of the sphere can be calculated as 6.1 kg / 2600 kg/m³ = 0.002346 m³.

According to Archimedes' principle, the volume of water displaced is equal to the volume of the sphere.

Volume displaced = 0.002346 m³

The buoyant force formula is:

Where:

is the fluid's density,

g represents the acceleration due to gravity,

V indicates the volume displaced.

Referencing the free-body diagram of the sphere shown in the image:

Acceleration due to gravity = 9.81 ms⁻²

Tension force = 26 N

Using these in the equation to ascertain the liquid density yields:

Thus, the density of the liquid = 1470.43 kg/m³

More information is needed, but in general, a polyatomic ion consists of multiple atoms bonded together, often with instability that affects their bonding patterns.

An r-selected species has a significantly faster reproductive rate compared to K-selected species.

The focus of r-selected species is on quick maturation and reproduction. They are likely to breed during short periods when water supply is available, thus enhancing their survival chances.

Conversely, K-selected species prioritize nurturing their young and tend to reproduce later. Due to the longer maturation time before breeding, by the time K-selected species are ready, the water supply may be depleted, leading to lower survival odds.

Hope this clarifies!
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~Collinjun0827, Junior Moderator

Unused chemicals should never be returned to their original containers, as this could lead to contamination. The leftover chemicals should be disposed of in the appropriate waste bin. If there is uncertainty about the procedure, consult your teacher.

The appropriate answer is option E. Gibbs free energy can be expressed using the equation: ΔG = ΔH - TΔS, where ΔH denotes the change in enthalpy of the reaction, T is the reaction temperature, and ΔS signifies entropy change. For our calculations, we have ΔH = -720.5 kJ/mol which converts to -720500 J/mol (given that 1 kJ = 1000 J), ΔS = -263.7 J/K, and T = 141.0°C, which equals 414.15 K. Consequently, the Gibbs free energy for the specified reaction at 141.0°C is calculated as -611.3 kJ/mol.