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icang
2 months ago
6

For the decomposition of phosphorous pentachloride to phosphorous trichloride and chlorine at 400K the KC is 1.1x10-2. Given tha

t 1.0g of phosphorous pentachloride is added to a 250mL reaction flask, find the percent decomposition after the system has reached equilibrium. PCl_5(g) PCl_3(g) Cl_2(g) K_C
Chemistry
1 answer:
KiRa [2.9K]2 months ago
7 0
Hello, in this context regarding the decomposition of phosphorus pentachloride: Considering the equilibrium constant is given, along with the initial concentration of phosphorus pentachloride, we can establish the law of mass action. To analyze the changes in concentration and the equilibrium state, an ICE table will be used. This will lead us to determine the equilibrium concentration of phosphorus pentachloride, which will ultimately allow us to compute the percent decomposition. Best regards.
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In a chemical reaction that takes place at a fixed pressure and volume, the enthalpy change (ΔH) is –585 kJ/mol. Will this react
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According to the sign convention, a negative ΔH indicates that the reaction is exothermic, resulting in a loss of heat and a reduction in temperature.

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Apex is a new internet streaming service. Read their advertisement from the local newspaper. Apex is the newest, fastest streami
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Answer:

B. Apex provides more channels per dollar compared to certain other streaming platforms.

Explanation:

Just completed the Quiz on Edgenuity.

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A mass of 5.4 grams of aluminum (al) reacts with an excess of copper (ii) chloride (cucl2) in solution, as shown below. 3cucl2 2
eduard [2782]

Answer:

The mass of copper generated is 19.07g

Explanation:

Let's write out the chemical equation;

3CuCl2 + 2Al → 2AlCl3 + 3Cu

3:   2:   2: 3

After confirming that the reaction is balanced, we can continue.

The problem asks for the mass of Cu produced from 5.4g of Al reacting.

Based on the equation, what is the relation between Al and Cu?

2 moles of Al would yield 3 moles of Cu

Expressing this in mass terms, we find;

mass = number of moles * molar mass

Mass of Aluminium = 2 * 26.98 = 53.98 g

Mass of Copper = 3 * 63.546 = 190.638g

This indicates that;

53.98 g of Al would react to create 190.638g of Cu

So, how much Cu would result from 5.4 g of Al?

This leads us to;

53.98 = 190.638

5.4 = x

By cross multiplication, we determine;

x = (190.638 * 5.4) / 53.98

x = 19.07 g

The mass of copper created is 19.07g

8 0
1 month ago
Ibuprofen, a headache remedy, contains 75.69% C, 8.80% H, and 15.51% O by mass and has a molar mass of 206 g/mol. Express your a
castortr0y [3046]

Answer:

A) The molecular formula for ibuprofen isC_{13}H_{18}O_2

B) The molecular formula for Cadaverine is C_{5}H_{14}N_2

C) The molecular formula for Epinephrine is C_9H_{13}O_3N_1

Explanation:

Element percentage in a compound:

\frac{\text{Number of atoms of element}\times \text{Atomic mass of element}}{\text{molecular mass of element}}\times 100

A) The composition of ibuprofen, used for headaches, consists of 75.69% carbon, 8.80% hydrogen, and 15.51% oxygen by weight.

Ibuprofen has a molar mass of 206 g/mol.

The proposed molecular formula for ibuprofen is =C_xH_yO_z

Count of carbon atoms in one ibuprofen molecule;

75.69\%=\frac{x\times 12 g/mol}{206 g/mol}\times 100

x=\frac{75.69\times 206 g/mol}{100\times 12 g/mol}=12.99\approx 13

Count of hydrogen atoms in one ibuprofen molecule;

8.80\%=\frac{y\times 1 g/mol}{206 g/mol}\times 100

y=\frac{8.80\times 206 g/mol}{100\times 1 g/mol}=18.12\approx 18

Count of oxygen atoms in one ibuprofen molecule;

15.51\%=\frac{z\times 16 g/mol}{206 g/mol}\times 100

z=\frac{15.51\times 206 g/mol}{100\times 16 g/mol}=1.99\approx 2

Molecular formula for ibuprofen:

= C_xH_yO_z= C_{13}H_{18}O_2

B) Cadaverine consists of 58.55% carbon, 13.81% hydrogen, and 27.40% nitrogen by weight

Cadaverine has a molar mass of 102.2 g/mol.

The proposed molecular formula for Cadaverine is =C_xH_yN_z

Count of carbon atoms in one Cadaverine molecule;

58.55\%=\frac{x\times 12 g/mol}{102.2 g/mol}\times 100

x=\frac{58.55\times 102.2 g/mol}{100\times 12 g/mol}=4.98\approx 5

Count of hydrogen atoms in one Cadaverine molecule;

13.81\%=\frac{y\times 1 g/mol}{102.2 g/mol}\times 100

y=\frac{13.81\times 102.2 g/mol}{100\times 1 g/mol}=14.11\approx 14

Count of nitrogen atoms in one Cadaverine molecule;

27.40\%=\frac{z\times 14 g/mol}{102.2 g/mol}\times 100

z=\frac{27.40\times 102.2 g/mol}{100\times 14 g/mol}=2.00\approx 2

Molecular formula for Cadaverine:

= C_xH_yN_z= C_{5}H_{14}N_2

C) Epinephrine includes 59.0% carbon, 7.1% hydrogen, 26.2% oxygen, and 7.7% nitrogen by weight

Epinephrine has a molar mass of 180 g/mol.

The proposed molecular formula for Epinephrine is =C_xH_yO_zN_w

Count of carbon atoms in one Epinephrine molecule;

59.0\%=\frac{x\times 12 g/mol}{180 g/mol}\times 100

x=\frac{59.0\times 180 g/mol}{100\times 12 g/mol}=8.85\approx 9

Count of hydrogen atoms in one Epinephrine molecule;

7.1\%=\frac{y\times 1 g/mol}{180 g/mol}\times 100

y=\frac{7.1\times 180 g/mol}{100\times 1 g/mol}=12.78\approx 13

Count of oxygen atoms in one Epinephrine molecule;

26.2\%=\frac{z\times 16 g/mol}{180 g/mol}\times 100

z=\frac{26.2\times 180 g/mol}{100\times 16 g/mol}=2.94\approx 3

Count of nitrogen atoms in one Epinephrine molecule;

7.7\%=\frac{w\times 14 g/mol}{180 g/mol}\times 100

w=\frac{7.7\times 180 g/mol}{100\times 14 g/mol}=0.99\approx 1

Molecular formula for Epinephrine:

= C_xH_yO_zN_w= C_9H_{13}O_3N_1

7 0
3 months ago
There is water on the pan of the scale as you measure the mass of an object. If you were to ignore the water, what would be the
castortr0y [3046]
Density is defined as the "mass per unit volume" of an object.

Thus, for an object weighing 100 grams with a volume of 100 milliliters, the density calculates to 100 grams / 100 ml.

When weighing the object, if there is water on the scale's surface, it will contribute additional weight, making the object seem heavier than its actual mass. Consequently, you might mistakenly conclude that the density is GREATER than it truly is.

For instance, if there were 5 ml of water on the scale, with water's density being 1 gram per milliliter (1 g/ml), it would add 5 grams to the object's weight. Using the previous example, the object's mass appears as 105 grams instead of 100 grams. Thus, you would calculate:

density = mass / volume
density = 105 grams / 100 ml
density = 1.05 g/ml

Thus, the effect on density would be to misleadingly suggest it is greater.

I hope this is helpful!

Best of luck
6 0
1 month ago
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