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Fynjy0
4 days ago
13

The law of cosines is a^2+b^2-2abcosC=c^2. Find the value of 2abcosC.

Mathematics
2 answers:
Zina [9.1K]4 days ago
5 0

Response:

(D)7=2abcosC

Step-by-step breakdown:

The given figure shows c=1, a=2, and b=2, so we apply the law of cosines and obtain

c^2=a^2+b^2-2abcosC

By substituting the provided figures, we solve for

(1)^2=(2)^2+(2)^2-2abcosC

1=4+4-2abcosC

1=8-2abcosC

1-8=-2abcosC

-7=-2abcosc

7=2abcosC

Therefore, the value of 2abcosC is 7.

Thus, option (D) is the right choice.

zzz [9K]4 days ago
4 0
2ab x cos(C) = 7 since

a^2 + b^2 - 2ab x cos(C) = c^2
2ab x cos(C) = a^2 + b^2 - c^2
2ab x cos(C) = 2^2 + 2^2 - 1^2
2ab x cos(C) = 7
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