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nydimaria
4 days ago
5

Sanjeet paid $32.85 for a file and 3 identical pens.Leon paid $83.50 for 2 such files and 8 such pens.Find the cost of 1 pen.

Mathematics
1 answer:
tester [8.8K]4 days ago
5 0
1 file + 3 pens costs $32.85    --------------- (1)  2 files + 8 pens = $83.50    ----------------(2) (1) multiplied by 2 gives us: 2 files + 6 pens = $65.70    ----------------(1a) (2) - (1a):  2 pens = $17.80 hence 1 pen = $8.90 ------------------------------------ Answer: The price of one pen is $8.90.
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A triangle has sides that measure 4 units, 6 units, and 7.21 units. What is the area of a circle with a circumference that equal
PIT_PIT [9117]

Step-by-step explanation:

Given are

Sides of the triangle measure 4 units, 6 units, and 7.21 units.

We need to compute the area of a circle whose circumference matches the triangle's perimeter.

The triangle's perimeter corresponds to the circle's circumference.

4 + 6 + 7.21 = 2πr, where r is the radius of the circle.

r = 2.73 units

Circle's area is:

A=\pi r^2\\\\A=3.14\times (2.73)^2\\\\A=23.402\ \text{units}^2

or

A = 24 square units

Thus, the circle’s area is 24 square units.

3 0
19 days ago
Using the extended Euclidean algorithm, find the multiplicative inverse of a. 1234 mod 4321 b. 24140 mod 40902
AnnZ [9099]

(a) The multiplicative inverse of 1234 (mod 4321) is x so that 1234*x ≡ 1 (mod 4321). We can apply Euclid's algorithm:

4321 = 1234 * 3 + 619

1234 = 619 * 1 + 615

619 = 615 * 1 + 4

615 = 4 * 153 + 3

4 = 3 * 1 + 1

Now we will express 1 as a linear combination of 4321 and 1234:

1 = 4 - 3

1 = 4 - (615 - 4 * 153) = 4 * 154 - 615

1 = 619 * 154 - 155 * (1234 - 619) = 619 * 309 - 155 * 1234

1 = (4321 - 1234 * 3) * 309 - 155 * 1234 = 4321 * 309 - 1082 * 1234

This reduces to

1 ≡ -1082 * 1234 (mod 4321)

Thus, the inverse is

-1082 ≡ 3239 (mod 4321)

(b) Since both 24140 and 40902 are even, their GCD cannot equal 1, indicating no inverse exists.

8 0
1 month ago
Carla can choose two of her three pairs of sneakers to take to a track meet. If the pairs of sneakers are called A, B, and C, wh
lawyer [9240]
The formula for determining the number of ways to select two pairs of sneakers from three pairs labeled A, B, and C is represented by 3C2 (3 combinations of 2), which calculates as 3! / (2!(3 - 2)!) = 3! / (2! x 1!) = (3 x 2) / (2 x 1) = 3. Therefore, the sample space is S = {AB, AC, BC}.
5 0
1 day ago
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Suppose we are given 4 sets A, B, C, D such that A ⊆ B and C ⊆ D such that A and C have no elements in common. Prove or give a c
babunello [8412]

Here’s a counterexample: consider

B = \{1, 2, 3, 4, 5\},\quad D = \{A, B, C, D, 5\}

Select the subsets in the following manner:

A = \{1, 5\},\quad C = \{A, B, C\}

It's accurate that A\subseteq B and C\subseteq D and that A\cap C=\emptyset, but A\cap D = \{5\}

8 0
19 days ago
On a coordinate plane, 2 exponential fuctions are shown. Function f (x) decreases from quadrant 2 into quadrant 1 and approaches
Zina [9171]

Answer:

g(x)=6(3)^x

Step-by-step explanation:

We are provided with the information that

f(x)=6(\frac{1}{3})^x

Function f is decreasing as it moves from quadrant 2 to quadrant 1, tending towards y=0

It intersects the y-axis at the point (0,6) and goes through (1,2).

Function g(x) also approaches y=0 in quadrant 2, but increases in quadrant 1.

It passes through (-1,2) and crosses the y-axis at (0,6).

Reflection across y-axis:

The transformation rule is identified as

(x,y)\rightarrow (-x,y)

Applying this rule, we derive

g(x)=6(\frac{1}{3})^{-x}=6(3)^x

Then, by substituting

x^{-a}=\frac{1}{x^a}

for x=-1

g(-1)=6\times (\frac{1}{3})=2

for x=0

g(0)=6

Consequently,g(x)=6(3)^x holds true.

8 0
16 days ago
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