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svet-max
5 days ago
7

What is the solution to –2|2.2x – 3.3| = –6.6? x = –3 x = 3 x = –3 or x = 0 x = 0 or x = 3

Mathematics
2 answers:
babunello [10.2K]5 days ago
6 0

x = 3

-2 | 2.2(3) - 3.3 | = -6.6

-2 | 6.6 - 3.3 | = -6.6

-2 | 3.3 | = -6.6

-2 * 3.3 = -6.6

-6.6 = -6.6

Inessa [11.1K]5 days ago
4 0

We start with

-2\left|2.2x-3.3\right|=-6.6

Step 1

Determine the initial solution

The first solution occurs when the value inside the absolute value is positive

-2[(2.2x-3.3)]=-6.6

Proceed to solve for x

-4.4x+6.6=-6.6\\-4.4x=-6.6-6.6 \\ -4.4x=-13.2\\x=3

Step 2

Identify the second solution

The second solution appears when the value inside the absolute value is negative

-2[-(2.2x-3.3)]=-6.6

Proceed to solve for x

4.4x-6.6=-6.6\\ 4.4x=0\\x=0

Thus

the solution is

x = 0 or x = 3

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lawyer [11277]

Response:

When combining two fractions that each exceeds 1/2, their sum will invariably exceed 1.

Detailed breakdown: 1/2 + 1/2 = 1    

Since both fractions exceed this amount, it is evident that the sum must as well.

Examples: 2/3+3/4= 1 5/12        4/6+6/9= 1 1/3

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6 0
22 days ago
If mJI = (3x+2)°, mHLK = (15x-36)°, and m∠HML = (8x-1)°, find mHLK
lawyer [11277]

Response:

The measure of mHLK is "(204)°".

Step-by-step breakdown:

Given values include:

mJI = (3x+2)°

mHLK = (15x-36)°

and,

m∠HML = (8x-1)°

then,

What is mHLK?

Now,

Utilizing the chord-chord angle formula, we find

mHMK=\frac{1}{2}(mJL+mHLK)

Inserting the known values into the equation gives us

⇒  (8x-1)=\frac{1}{2}(15x-36+3x+2)

By carrying out cross-multiplication, we arrive at

⇒  2(8x-1)=18x-34

⇒  16x-2=18x-34

By subtracting "18x" from both sides, we obtain

⇒  16x-2-18x=18x-34-18x

⇒  -2x-2=-34

Upon adding "2" to both sides, we end up with

⇒  -2x=-34+2

⇒  -2x=-32

⇒  x=\frac{32}{2}

⇒  x=16

By substituting the value of "x" into mHLK = (15x-36)°, we calculate

⇒ (15x-36)° = (15×16-36)°

⇒                = (240-36)°

⇒                = (204)°

Thus, mHLK = (204)°

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1 month ago
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Answer:

B. The triangle.

Step-by-step explanation:

The number of sides decreases by one as you progress down the list.

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Svet_ta [11363]
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Then we will assign a variable to represent the value and also shift the repeating segment to the left.

Essentially, the concept here is that we can denote the repeating portion with a variable, let's say "x", and move forward with the calculation;

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\bf thus\qquad \begin{array}{llll}
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\end{array}\qquad \implies 100x=575+x
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The response is A

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