I believe the correct response is option C.
Answer:
At the α = 0.10 level, there is no substantial evidence indicating that the average vertical jump for students at this school differs from 15 inches.
Step-by-step explanation:
A hypothesis test is necessary to verify the assertion that the average vertical jump of students diverges from 15 inches.
The null and alternative hypotheses are:

The significance level is set at 0.10.
The sample mean recorded is 17, and the sample standard deviation is 5.37.
The degrees of freedom are calculated as df=(20-1)=19.
The t-statistic is:

The two-tailed P-value corresponding to t=1.67 is P=0.11132.
<pSince this P-value exceeds the significance level, the result is not significant. Therefore, the null hypothesis remains unchallenged.
At the α = 0.10 level, there is no compelling evidence that the average vertical jump of students at this school deviates from 15 inches.
Mel descends 50-35=15 feet in 5-2=3 seconds. Thus, her descent rate is 15/3=5 ft/sec.
Victor descends 60-50=10 feet in 4-1=3 seconds. Hence, his descent rate is 10/3=3⅓ ft/sec. Mel is faster, traveling at 5 ft/sec.
I appreciate you sharing your question. A potential solution to the problem is that 10 ones can be converted into 1 ten, resulting in the total of the ungrouped values of 4,000 + 900 + 10, which sums up to 5,000. I trust my explanation will be beneficial.
I found that there are All Real Numbers (infinite solutions); what are your choices for answers?