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podryga
5 days ago
12

The E. coli bacteria has a volume of 6 µm3 . In optimal conditions, an E. coli bacteria will double about every 30 minutes. Unde

r these conditions, how long will it take for a single bacterium to grow to fill a thimble with volume 1 cm3 ? How long will it take for the volume to fill the entire earth 1.08 × 108 km3 ?
Mathematics
1 answer:
babunello [11.8K]5 days ago
4 0
Answer: It would take approximately 19 hours and 15 minutes for one bacterium to grow and occupy the volume of a thimble measuring 1 cm3. In contrast, filling the entire Earth would require 57.6 hours. Step-by-step explanation: The growth of the bacteria can be modeled as a geometric sequence, with the time intervals forming an arithmetic sequence. Each geometric sequence is structured as follows: where 'a' represents the initial term and 'r' denotes the common ratio. Any term of the sequence can be calculated using the subsequent formula: Each arithmetic sequence has its format, defined as follows: in which 'a' is the first term and 'd' indicates the difference between the terms. The corresponding formula to locate any term in the sequence is provided. To solve this issue, we analyze the volume related to the bacterium growth. Note: Following this, we address the arithmetic sequence detailing the time in hours. The question is about determining how long it takes for a single bacterium to suffice for a thimble of volume 1 cm3. We will ascertain the value of 'n,' afterwards identifying its position in the arithmetic sequence. Note: We will apply certain logarithmic properties to find 'n': log 2 = 0.30 and log 3 = 0.48. Now, let's find the respective values in the arithmetic series. It takes roughly 19 hours and 15 minutes for a single bacterium to fill a thimble 1 cm3 in size. As for the time taken to fill the entire Earth, measured at 1.08 × 108 km3, we proceed in the same manner as before.
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Which is the solution of the quadratic equation (4y-3)^2=72 ?
babunello [11817]
Greetings: 
<span>(4y-3)²=72 
4y-3 = </span>±√72
thus, y= (3+√72) /4   or y= (3 - √72) /4
7 0
1 month ago
10 times as many as blank hundreds or 60 hundreds is blank thousands
Svet_ta [12734]

The result of multiplying 10 by 6 hundreds equals 60 hundreds, which can also be expressed as 6 thousands.

Explanation

This can be simplified as follows:

  • 10 times a given quantity of _____ hundreds results in 60 hundreds
  • 60 hundreds convert to _____ thousands

We will divide this into two segments:

\boxed{ \ 10 \times (N \times 100) = 60 \times 100 \ }... Equation-1

\boxed{ \ 60 \times 100) = M \times 1,000 \ }... Equation-2

This straightforward multiplication relates to the place value system. We need to perform calculations to find the values of N and M.

Initially, let's focus on Equation-1.

We will move the variable M to one side of the equation in order to isolate it and solve for its value.

\boxed{ \ 10 \times (N \times 100) = 60 \times 100 \ }

\boxed{ \ 1,000 \times N = 6,000 \ }

Both parts will be divided by 1,000, essentially being multiplied by \frac{1}{1,000}.

\boxed{ \ \frac{1}{1,000} \times 1,000 \times N = \frac{1}{1,000} \times 6,000 \ }

Thus, we conclude with \boxed{\boxed{ \ N = 6 \ }}

Next, we process Equation-2 to derive M's value.

\boxed{ \ 60 \times 100) = M \times 1,000 \ }

\boxed{ \ 6,000 = M \times 1,000 \ }

Rearranging this equation to place M on the left side appears as follows:

\boxed{ \ M \times 1,000 = 6,000 \ }

Again, both sides undergo division by 1,000, which translates to multiplication by \frac{1}{1,000}..

\boxed{ \ \frac{1}{1,000} \times M \times 1,000 = \frac{1}{1,000} \times 6,000 \ }

This results in \boxed{\boxed{ \ M = 6 \ }}

- - - - - - -

Alternative approach for the second step:

60 hundreds equals to __ thousands

\boxed{ \ 6 \times 10 \ hundreds = \ M \ thousands} \ }

\boxed{ \ 6 \times thousands = \ M \ thousands} \ }

\boxed{\boxed{ \ M = 6 \ }}

Additional resources

  1. A more detailed version of this topic
  2. 2 thousands 7 tens divided by 10 equals what?
  3. 100 is equivalent to 1/10 of which number?

Keywords: 10 times as many as, blank, hundreds, 60 hundreds, or, thousands, isolate, operations, multiply, divide, fraction, both sides, equal, the opposite, both sides are multiplied by, divided by, rearrange

4 0
1 month ago
Read 2 more answers
During batting practice, two pop flies are hit from the same location, 2 s apart. The paths are modeled by the equations h = -16
Inessa [12570]

Answer:

2.5 seconds after the initial ball was struck.

Step-by-step explanation:

The height equations are:

  • h = -16t² + 56t
  • h = -16t² + 156t - 248

At the point where the balls intersect, both heights are alike, therefore:

-16t² + 56t = -16t² + 156t - 248

-16t² + 56t + 16t² - 156t + 248 = 0

- 100t + 248 = 0

248 = 100t

t = 248/100

t = 2.48 ≈ 2.5

4 0
1 month ago
Billy Jo's school is selling tickets to a Fall Festival. On the first day of ticket sales the school sold 3 adult ticket and 8 s
PIT_PIT [12445]
Y = 6 Here’s a step-by-step explanation: On the initial day of ticket sales, the school sold 3 adult tickets and 8 student tickets for a total of $72. On the following day, the school collected $152 from 7 adult tickets and 16 student tickets. What is the price of a student ticket? Day 1: 3x + 8y = 72 Day 2: 7x + 16y = 152 This leads to a system of equations. By manipulating these equations, we find: Ultimately, y = 6. If you wish to continue from this point, substituting y into the equation will give the value for x.
6 0
22 days ago
A trust fund worth $25,000 is invested in two different portfolios, this year, one portfolio is expected to earn 5.25% interest
Leona [12618]

Answer:

A sum of $12,000 should be allocated at an interest rate of 5.25%, while $13,000 should be put in at 4%.

Step-by-step explanation:

Recall that

The simple interest formula is given by

I=P(rt)

where

I represents the total interest earned,

P is the initial investment,

r stands for the interest rate, and

t is the number of time periods.

Define

x as the amount invested at 5.25%,

and (25,000 - x) as the amount put in at 4%.

From the problem,

t=1\ year\\ P_1=\$x\\P_2=\$(25,000-x)\\r_1=0.0525\\r_2=0.04\\I=\$1,150

Plugging these into the formula:

I=P_1(r_1t)+P_2(r_2t)

1,150=x(0.0525*1)+(25,000-x)(0.04*1)

Now, isolate x:

1,150=0.0525x+1,000-0.04x

0.0525x-0.04x=1,150-1,000

0.0125x=150

x=\$12,000

|$25,000-x=\$13,000

Hence, investing $12,000 at 5.25% and $13,000 at 4% meets the required interest condition.

6 0
1 month ago
Read 2 more answers
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