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Alex_Xolod
2 months ago
9

Two fathers and two sons own 21 horses. They are moving to different parts of the country and want to divide the horses evenly a

mong themselves. How is this possible?
Mathematics
1 answer:
tester [12.3K]2 months ago
7 0
They cannot possess the same number of horses; let me clarify. If you divide 21 horses among four individuals, you would perform 21/4, yielding 5.25, implying that fractional horses are unfeasible. Therefore, at least one individual must have 6 horses instead of 5. Possibly, this is what your instructor wants you to understand. For an even distribution, they could sell one horse, making it 20, so each would then have 5 horses. Alternatively, they might share the extra horse to rotate its usage.
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Zayed is helping his classmates get ready for their math test by making them identical packages of pencils and calculators. He h
Svet_ta [12734]
To find the maximum number of identical packs we see we have 72 pencils and 24 calculators.

This involves discovering the largest number that divides both 72 and 24 evenly,
which is known as the GCM or greatest common multiplier.

To determine the GCM, factor 72 into primes and group them:
72=2 times 2 times 2 times 3 times 3
24=2 times 2 times 2 times 3
Thus, the common grouping is 2 times 2 times 2 times 3, equating to 24.
Therefore, the maximum number of packs is 24.

For pencils:
72 divided by 24=3
Resulting in 3 pencils per pack.

For calculators:
24 divided by 24=1
So, 1 calculator per pack.

The outcome is 3 pencils and 1 calculator in each pack.
6 0
2 months ago
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the volume of a cone is 3πx3 cubic units and its height is x units. which expression represents the radius of the cone’s base, i
Inessa [12570]
The volume provided is 3Pi(x^3) with a radius of x. To determine the volume of a cone, the formula used is V= [1/3]Pi(r^2)*height. By substituting, we get [1/3]Pi(r^2)x = 3Pi(x^3). This simplifies to (r^2)x = 9(x^3). Eventually, we find that r^2 = 9x^2, which leads to r = sqrt[9x^2] = 3x. <span>Answer: r = 3x</span>
7 0
2 months ago
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What is the logarithm of the equilibrium constant, log K, at 25°C of the voltaic cell constructed from the following two half-re
lawyer [12517]

Answer:

4.0921 reflects the logarithm of the equilibrium constant.

Step-by-step explanation:

Fe^{2+} (aq) +2e^{-}\rightarrow Fe(s); ​E​° = - 0.41 V

Ag^+(aq) + e^-\rightarrow Ag(s); E° = 0.80 V

Iron has a negative reduction potential, indicating its tendency to lose electrons and undergo oxidation, and thus it will be at the anode.

E^{o}_{cell}=Reduction potential of cathode - Reduction potential of anode

E^{o}_{cell}=E^{o}_c-E^{o}_a

=0.80 V-(-0.41 V)=1.21 V

Fe^{2+} (aq) + 2e^{-}\rightarrow Fe(s); ​E​° = - 0.41 V

2Ag^+(aq) + 2e^-\rightarrow 2Ag(s); E° = 0.80 V

Net reaction: Fe(s)+2Ag^{+}\rightarrow Fe^{2+}+2Ag(s)

n = 2

To determine the equilibrium constant, we utilize the correlation with Gibbs free energy, as follows:

\Delta G^o=-nfE^o_{cell}

and,

\Delta G^o=-RT\ln K_{eq}

Aligning these two equations yields:

nfE^o_{cell}=RT\ln K_{eq}

where,

n = electrons transferred = 2

F = Faraday's constant = 96500 C

E^o_{cell} = standard electrode potential of the cell = 1.21 V

R = gas constant = 8.314 J/K.mol

T = reaction temperature = 25^oC=[273+25]=298K

Substituting values into the equation, we arrive at:

2\times 96500\times 1.21 V=8.314\times 298\times \ln K_{eq}

\ln K_{eq}=9.3478

\log K_{eq}=\frac{9.3478}{2.303}=4.0921

4.0921 represents the logarithm of the equilibrium constant.

7 0
2 months ago
hury!!!! Which system is equivalent to StartLayout Enlarged left-brace 1st row y = negative 2 x squared 2nd row y = x minus 2 En
tester [12383]

Response:

The third option is correct

Step-by-step explanation:

What is the inverse of y = 7x^2 – 10?

y = ±√(x + 10) / 7

y = ±√((x + 10) / 7)

x = ±√(x / 7) + 10

y = ±√(x) / 7 ± √(10) / 7

8 0
1 month ago
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Suppose that you have two different algorithms for solving a problem. to solve a problem of size n, the first algorithm uses exa
tester [12383]
<span>We have two expressions: n(log(n)) and n3=2. The second expression involves fewer operations. From it, we can derive n = 2/3. For the left-hand side to equal the right-hand side, n cannot go beyond 2/3. No further operations can be applied at that level. Conversely, if we set n = 10, we find 10(log(10)) = 1. As we escalate n to 100, 100(log(100)) equals 200, and for n = 300, 300(log(300)) results in about 743.1. The logarithmic function increases without limit, while for the first operation, once n hits 2/3, it halts. Therefore, the second expression has fewer operations overall.</span>
5 0
2 months ago
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