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Alex_Xolod
3 days ago
9

Two fathers and two sons own 21 horses. They are moving to different parts of the country and want to divide the horses evenly a

mong themselves. How is this possible?
Mathematics
1 answer:
tester [8.8K]3 days ago
7 0
They cannot possess the same number of horses; let me clarify. If you divide 21 horses among four individuals, you would perform 21/4, yielding 5.25, implying that fractional horses are unfeasible. Therefore, at least one individual must have 6 horses instead of 5. Possibly, this is what your instructor wants you to understand. For an even distribution, they could sell one horse, making it 20, so each would then have 5 horses. Alternatively, they might share the extra horse to rotate its usage.
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On a rectangular soccer field, Sang is standing on the goal line 20 yards from the corner post. Jazmin is standing 99 yards from
Leona [9303]
To illustrate, Sang is positioned 20 yards from one corner, while Jazmin stands 99 yards from the same corner. Assuming this forms a rectangle (I prefer visual aids for explanations), the layout can be seen as:

99ft
A ------------------------- B
| |
20 ft | |
| |
C -------------------------- D

The task involves calculating the diagonal distance between points C and B, which divides the rectangle into two triangles. Consequently, in triangle ABC, side CB represents the longest side, or the hypotenuse. Thus, the Pythagorean Theorem can be applied to solve this.

A^2 + B^2 = C^2
99^2 + 20^2 = C^2
9,801 + 400 = C^2
10,201 = C^2

Now solve for C by taking the square root of 10,201.

sqr (10,201) = C
C = 101 yards

3 0
9 days ago
A triangle’s height is 6c meters and the base is c – 1 meters. Brian knows that the area of the triangle is 18 square meters and
tester [8870]

Answer:

I find it frustrating when responses don't start with A, B, C, or D, but in this instance, the correct choice is B.

Step-by-step explanation:


9 0
27 days ago
Read 2 more answers
Which number can each term of the equation be multiplied by to eliminate the fractions before solving? m – negative StartFractio
zzz [9093]

Answer: To remove fractions prior to solving, each term in the equation must be multiplied by 4.

Step-by-step explanation:

Consider the given expression:

-\frac{3}{4}m-\frac{1}{2}=2+\frac{1}{4}m

It is essential to simplify this before attempting to solve it.

Since the denominators differ, identifying the Least Common Denominator (LCD) is necessary.

Break down the denominators into their prime components:

4=2*2=2^2\\2=2

Select 2^2, as it possesses the greatest exponent. Thus:

LCD=2^2=4

Ultimately, to remove the fractions before solving, multiply both sides by 4:

(4)(-\frac{3}{4}m)-(4)(\frac{1}{2})=(4)(2)+(4)(\frac{1}{4}m)\\\\-3m-2=8+m

7 0
24 days ago
Kim's business earns $10,000 per month. Kim's non-employee expenses are $3,000 per month. If Kim wants $2,000 in profit per mont
AnnZ [9126]

Response:

The monthly income of Kim's business is $10,000.

Every month, Kim spends $3,000 on non-employee costs.

To achieve a monthly profit of $2,000, the highest possible expenditure for employees is calculated as follows:

10000 - 3000 - 2000 = 5000

With the cost of each employee being $1,000 a month, Kim can hire a maximum of 5000/1000 = 5 employees.

Hope this is useful

:)

8 0
10 days ago
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.580 80 repeating as fraction
Svet_ta [9567]
To start, we will shift the non-repeating segment of the decimal to the left side by dividing by a power of 10.

Then we will assign a variable to represent the value and also shift the repeating segment to the left.

Essentially, the concept here is that we can denote the repeating portion with a variable, let's say "x", and move forward with the calculation;

\bf 0.580\overline{80}\implies \boxed{\cfrac{5.80\overline{80}}{10}}\qquad \textit{now, let's say }x= 5.80\overline{80}\\\\
-------------------------------

\bf thus\qquad \begin{array}{llll}
100\cdot x&=&580.80\overline{80}\\
&&575+5.80\overline{80}\\
&&575+x
\end{array}\qquad \implies 100x=575+x
\\\\\\
99x=575\implies x=\cfrac{575}{99}\qquad therefore\qquad \boxed{\cfrac{5.80\overline{80}}{10}}\implies \cfrac{\quad \frac{575}{99}\quad }{10}
\\\\\\
\cfrac{\quad \frac{575}{99}\quad }{\frac{10}{1}}\implies \cfrac{575}{99}\cdot \cfrac{1}{10}\implies \cfrac{575}{990}\implies \stackrel{simplified}{\cfrac{115}{198}}

you can verify that using your calculator.
4 0
4 days ago
Read 2 more answers
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