Answer:
There is a probability of 24.51% that the weight of a bag exceeds the maximum permitted weight of 50 pounds.
Step-by-step explanation:
Problems dealing with normally distributed samples can be addressed using the z-score formula.
For a set with the mean 
and a standard deviation 
, the z-score for a measure X is calculated by
Once the Z-score is determined, we consult the z-score table to find the related p-value for this score. The p-value signifies the likelihood that the measured value is less than X. Since all probabilities total 1, calculating 1 minus the p-value gives us the probability that the measure exceeds X.
For this case
Imagine the weights of passenger bags are normally distributed with a mean of 47.88 pounds and a standard deviation of 3.09 pounds, thus 
What probability exists that a bag’s weight will surpass the maximum allowable of 50 pounds?
That translates to 
Thus
has a p-value of 0.7549.
<pthis indicates="" that="" src="https://tex.z-dn.net/?f=P%28X%20%5Cleq%2050%29%20%3D%200.7549" id="TexFormula10" title="P(X \leq 50) = 0.7549" alt="P(X \leq 50) = 0.7549" align="absmiddle" class="latex-formula">.
Additionally, we have that
There is a probability of 24.51% that the weight of a bag will exceed the maximum allowable weight of 50 pounds.
</pthis>
The problem's sample space consists of a selection of roses and hibiscus in various colors, totaling 315 flowers. Among these, 20 are pink roses, making the probability of selecting a pink rose 20/315, or approximately 0.063.
Define x as the first mile marker, thus x + 1 corresponds to the second mile marker. This can be expressed as x + (x + 1) = 561, which simplifies to 2x + 1 = 561. Therefore, 2x equals 560, leading to x being 280. Consequently, the first mile marker is 280, and the second mile marker is 281.
9 is the highest common factor
Answer:
b
Step-by-step explanation:
The correct option is (B). Correcting the error will lead to a decrease in the mean, since 8 is less than 18, and it will also lower the standard deviation because the value of 8 is nearer to the mean compared to 18.
