21. A college professor recorded the speed with which students ran out the door after class after taking the final exam (using a

Answer:

The 10th term in the geometric progression is 29.

Step-by-step explanation:

Given: In a geometric series, [T3 = 18] and [T6 = 486].

To find: The term [T10]?

Solution:

A geometric sequence takes the form [a, ar, ar^2,...]

Where, a represents the first term, and r denotes the common ratio.

The nth term is expressed as [Tn = a * r^(n-1)]

From the information provided: [T3 = a * r^2 = 18]

And [T6 = a * r^5 = 486]

By dividing the second equation by the first:

[(a * r^5) / (a * r^2)] = 486 / 18

[r^3 = 27]

Taking the cube root provides: r = 3.

Inserting r into one of the equations allows us to solve for a.

Substituting r gives: [T3 = a * r^2 = 18]

Thus, the first term is a = 2, and the common ratio is r = 3.

The 10th term in the geometric progression is computed as:

[T10 = a * r^(10-1)]

[Thus, T10 = 29.]

Answer:

(-16x + 13)° + (-20x + 23)° = 180° (ángulo recto)

-16x° + 13° - 20x° + 23° = 180°

-36x° + 36° = 180°

-36x° = 180° - 36°

-36x° = 144°

-x° = 144°/(-36)

x° = 36°

Espero que puedas conocer esta respuesta

Answer:

0.32

Step-by-step explanation:

P(B|A) = P(A∩B) / P(A)

0.25 = 0.08 / P(A)

P(A) = 0.32