A ball is dropped from the top of a building.After 2 seconds, it’s velocity is measured to be 19.6 m/s. Calculate the accelerati
2 answers:
The provided information is as follows: Initial velocity u = 0, Final velocity v = 19.6 m/s, and time t = 2 seconds. The relationship among initial velocity, final velocity, and acceleration is described by the equation
v = u + at. Thus, inserting the given values into the formula yields 19.6 m/s = 0 + . Consequently, it follows that a = 9.8
. Therefore, we conclude that the acceleration of the dropped ball is 9.8 .
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Answer: The resulting speed is 
. Option (a) stands as the correct choice. Explanation: Given the context, the potential difference entails calculations linked to speed assessment. If instead accelerated through a different potential difference, the resulting speed will be computed accordingly.
Answer:
3.5 cm
Explanation:
mass, m = 50 kg
diameter = 1 mm
radius, r = half the diameter = 0.5 mm = 0.5 x 10^-3 m
L = 11.2 m
Y = 2 x 10^11 Pa
Cross-sectional area of the wire = π r² = 3.14 x 0.5 x 10^-3 x 0.5 x 10^-3
= 7.85 x 10^-7 m^2
Let the change in length of the wire be ΔL.
The equation for Young's modulus is given by
ΔL = 0.035 m = 3.5 cm
Thus, the wire stretches by 3.5 cm.
Answer:
0.0016 cm
Explanation:
= The thermal expansion coefficient for brass =
= The thermal expansion coefficient for glass =
= Temperature change =
= Original radius = 4 cm
The change in radius is described by
The radius difference between the lid and the jar
The gap measures 0.0016 cm or 0.000016 m