Answer:
11.56066 m/s
Explanation:
m = Mass of individual
v = Velocity of individual = 13.4 m/s
g = Gravitational acceleration = 9.81 m/s²
v' = Velocity of the individual after dropping
At the surface, kinetic and potential energy will equalize
The cliff's height is 9.15188 m
Define fall height as h' = 2.34 m
The person's speed is 11.56066 m/s
Response:
Once it has crossed, the locomotive requires 17.6 seconds to achieve a speed of 32 m/s.
Details:
The locomotive's acceleration is 1.6
The duration taken to pass the crossing is 2.4 seconds.
We can apply the motion equation, v = u + at, where v represents final velocity, u indicates initial velocity, a denotes acceleration, and t signifies time.
When the speed reaches 32 m/s, we have v = 32 m/s, u = 0 m/s, and a= 1.6 .
32 = 0 + 1.6 * t
t = 20 seconds.
Therefore, the locomotive attains a speed of 32 m/s after 20 seconds, and it passes the crossing in 2.4 seconds.
Thus, after clearing the crossing, it takes an additional 17.6 seconds to reach the speed of 32 m/s.
Answer:
a = 18.28 ft/s²
Explanation:
the values provided are:
duration of force application, t= 10 s
Work done = 10 Btu
mass of the object = 15 lb
acceleration, a =? ft/s²
1 Btu = 778.15 ft.lbf
thus, 10 Btu = 7781.5 ft.lbf
m = 0.466 slug
So,
the work is equivalent to the change in kinetic energy
The acceleration of the object is therefore
a = 18.28 ft/s²
the constant acceleration of the object is calculated to be 18.28 ft/s²