Let
A (1,6)------> denotes the location of <span>Brianna's house on a map
B </span>(5,3)------> indicates the location of
Jordan's house on a map
It’s clear that <span>One possible path from Brianna's residence to Jordan's home is a straight line (which represents the shortest distance) </span>
Utilizing a graphing tool
refer to the attached diagram
To calculate the distance between points A and B, we use:
d=√[(y2-y1)²+(x2-x1)²]-----> d=√[(3-6)²+(5-1)²]----> d=√[3²+4²]
Ultimately, d=√25----> d=5 units
Thus, the distance from Brianna's house to Jordan's house is 5 units.
The area calculation for the shaded section, as seen in the attached diagram, involves subtracting the area of the kite from that of the rectangle. The area of the rectangle is calculated as (3x+x)*(x+x), which simplifies to 4x*2x, equating to 8x². The area of the kite is determined using the formula (1/2)*[d1*d2], where d1 and d2 represent the diagonals, specifically d1=4x and d2=2x. Therefore, the area of the kite becomes (1/2)*[4x*2x], leading to 4x². Consequently, the area of the shaded region can be computed as 8x²-4x², resulting in 4x². Thus, the solution is 4x².
Answer:
El valor de x es 4.
Explicación paso a paso:
Se indica que el triángulo MRN surge al doblar un triángulo equilátero por la mitad.
Esto sugiere que el triángulo equilátero original es MNO y que NR actúa como bisectriz perpendicular (una línea que divide un segmento en dos partes iguales formando un ángulo recto).
La longitud del lado del triángulo es
NO = NS + SM = 6 + 2 = 8
Dado que un triángulo equilátero tiene todos sus lados iguales y NR es la bisectriz perpendicular, se tiene que
RM = MO/2 = 8/2 = 4
El valor de x es 4.
Answer:

The variable x lies within the interval of all positive real numbers less than 5 cm.
Detailed solution:
Problem statement:
Determine the volume of the open-topped box as a function of the side length x (in centimeters) of the square cutouts.
Refer to the provided diagram for clarity.
Define:
x → length in centimeters of each square cutout side
The volume of the box with open top can be written as:

Given this, we have:



By substitution:

Determine the domain of x:
Because:

Therefore:
Domain is the interval (0,5)
That means all real numbers strictly greater than zero and less than 5 cm are valid for x.
Hence, the volume V as a function of x is:
