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Neporo4naja
2 months ago
12

Two years ago your orange orchard contained 90 trees and the yield per tree was 80 bags of oranges. last year you removed 10 of

the trees and noticed that the yield per tree increased to 85 bags. assuming that the yield per tree depends linearly on the number of trees in the orchard, what should you do this year to maximize your total yield?
Mathematics
2 answers:
PIT_PIT [12.4K]2 months ago
8 0

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Inessa [12.5K]2 months ago
7 0

Respuesta:

Este año debe haber 69 árboles para obtener el máximo rendimiento.

Explicación paso a paso:

Sea el número de árboles = x.

Con 90 árboles, el rendimiento total es de 80 bolsas.

Es decir, el rendimiento por árbol = \frac{80}{90}=0.88

Con 80 árboles, el rendimiento total es de 85 bolsas.

Es decir, el rendimiento por árbol = \frac{85}{80}=1.06

Por lo tanto, por cada disminución de 10 árboles, el rendimiento por árbol aumenta en 1.06-0.88 = 0.18.

Así, el rendimiento por árbol, Y=1.06-\frac{x-80}{10}\times 0.18

es decir, Rendimiento por árbol = Y=2.5-0.018x

Luego, el rendimiento total, T = Número de árboles(x) × Rendimiento por árbol(Y)

es decir, Rendimiento total, T = x(2.5-0.018x)

es decir, Rendimiento total, T = 2.5x-0.018x^2

Ahora, para maximizar el rendimiento total, derivamos T con respecto a x y lo igualamos a 0.

Obtenemos, T'=0 implica 2.5-0.036x=0

es decir, 2.5=0.036x

es decir, x = 69

Por lo tanto, este año deben haber 69 árboles para conseguir el máximo rendimiento.

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Triangle JKL is equilateral. One side of the triangle, JL, is a diameter of circle M. Which is true about line segments JK and K
Inessa [12570]
It can be deduced that because line JL serves as a diameter for a circle, lines JK and KL function as the tangents of that circle. A tangent is defined as "a line that touches a curve at a singular point without intersecting it." Thus, both lines contact the perimeter of circle M, confirming they are tangents.
7 0
1 month ago
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Which number line represents the solutions to |–2x| = 4? A number line from negative 10 to 10 in increments of 2. Two points, on
Zina [12379]

Answer:

Two solutions exist, specifically one at -2 and another at 2.

Step-by-step explanation:

|–2x| = 4

2x = 4 leads to x = 2 and

2x = -4 leads to x = -2.

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2 months ago
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Use the alternative curvature formula K=|a x v|/|v|^3 to find the curvature of the following parameterized curves.
PIT_PIT [12445]

Answer:

K=\frac{2}{(4t^{2}+1)^{\frac{3}{2}}}

Step-by-step explanation:

First, we determine v and a as:

v(t)=\frac{dr(t)}{dt}=(2t,1,0)

a(t)=\frac{dv(t)}{dt}=(2,0,0)

Subsequently, we compute the cross product and substitute it into the formula for k

a(t) X v(t) = (0,0,2)

| a(t) X v(t) | = 2

| v |^{3} = (4t^{2}+1)^{\frac{3}{2}}

Thus, we conclude

K=\frac{2}{(4t^{2}+1)^{\frac{3}{2}}}

I trust this is of assistance to you

best regards

8 0
1 month ago
a barangay has 1000 individuals and its population doubles every 60 years. Give an exponential model for the barangay's populati
Svet_ta [12734]

Answer:

P(t) = 1000e^(0.01155)t

Step-by-step explanation:

The population of the barangay can be modeled using the exponential function;

P(t) = P0e^kt

P(t) reflects the population after t years

P0 denotes the initial population

t indicates the time

With an initial population of 1000, we set P0 = 1000

Given that the population doubles every 60 years, at t = 60, it holds that P(t) = 2P0

Inserting that into the equation yields

2P0 = P0e^k(60)

2 = e^60k

Taking the natural logarithm of both sides

ln2 = lne^60k

ln2 = 60k

k = ln2/60

k = 0.01155

Inserting the determined k value and P0 into the function gives

P(t) = 1000e^(0.01155)t

Thus, the exponential model for the population of the barangay is

P(t) = 1000e^(0.01155)t

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1 month ago
A rectangle has a perimeter of 18 inches. a new rectangle is formed by doubling the with W in tripling the length L as shown the
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a) The original rectangle has dimensions of length = 5 and width = 4. b) The new rectangle has dimensions of length = 15 and width = 8. Step-by-step explanation: The formula for the perimeter of a rectangle is 2(l+w). For the original rectangle, this results in 18 = 2(l+w), which simplifies to 18 = 2l + 2w. The new rectangle's perimeter is expressed as 46 = 2(3l + 2w), which leads to 46 = 6l + 4w. By solving these equations, the original lengths can be derived as 5 inches for the length and 4 inches for the width.
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