total mass of the Syringe. Record it in the correct row of the data table. how many kilograms would it be?

Respuesta:

0.16 M

Explicación:

Teniendo en cuenta:

O sea,

Dado que:

Para :

Molaridad = 0.200 M

Volumen = 20.0 mL

Convierte mL a L:

1 mL = 10⁻³ L

Entonces, volumen = 20.0×10⁻³ L

Los moles de son:

Moles de = 0.004 moles

Para :

Molaridad = 0.400 M

Volumen = 30.0 mL

Convertimos mL a L:

1 mL = 10⁻³ L

Volumen = 30.0×10⁻³ L

Entonces, los moles de son:

Moles de = 0.012 moles

Según la reacción:

1 mol de reacciona con 1 mol de

Por lo tanto,

0.012 mol de reacciona con 0.012 mol de

Moles disponibles de = 0.004 mol

El reactivo limitante es el que está en menor cantidad, entonces es el limitante (0.004 < 0.012).

La formación del producto depende del reactivo limitante, así que,

1 mol de reacciona con 1 mol de y produce 1 mol de

0.004 mol de reacciona con 0.004 mol de y genera 0.004 mol de

Los moles restantes de son: 0.012 - 0.004 = 0.008 mol

El volumen total es 20 + 30 mL = 50 mL = 0.050 L

Por lo que la concentración del ion bario, , después de la reacción es:

Answer:

K2X

Explanation:

The term valency refers to an element's capacity to combine with other elements. This property determines how an element is represented in a chemical compound's formula.

For magnesium and element X, represented as MgX, magnesium typically has a valency of +2 in its compounds. The absence of the +2 in the formula implies that element X must possess a -2 valency, resulting in a cancellation of the valencies.

Furthermore, potassium is classified as an alkaline metal in group 1 of the periodic table, leading to an expected valency of +1.

When forming a compound with element X, a valency exchange occurs. Since X has a -2 valency, the resulting formula of the compound formed by the exchange will be K2X.

To find the mass of oxygen in the specified compound, we require the molar mass for both the compound and oxygen. We also establish the relationship between the number of moles of oxygen per mole of the substance. The calculation proceeds as follows:

90.0 g ( 1 mol / 86.91 g ) ( 1mol O / 1 mol Cl2O) ( 16 g / 1 mol ) = 16.57 g O

Answer:

B, D

Explanation:

We need to recognize that the ice will rise in temperature from -6.5 ºC to 0 ºC for it to change into water.

Let's define q₁ as the heat needed to warm the ice to 0ºC, and q₂ as the heat for the transition from solid to liquid.

The calculation for q₁ is as follows:

q₁ = s x m x ΔT, where s represents the specific heat of ice (2.09 J/gºC), m is the mass, and ΔT is the temperature difference.

For q₂, the enthalpy of fusion is computed as:

q₂ = C x ΔT

with C indicating the specific heat for the phase transition, denoted as AH in kJ/mol.

All necessary data for computing q₁, q₂, and the total heat change (q₁ + q₂) is provided.

q₁ = 25.0 g x (2.09 J/gºC) x (0 - (-6.5 ºC))

q₁ = 339.6 J = 0.339 kJ

q₂ = (25 g/18 g/mol) x 6.02 kJ/mol = 1.39 x 6.02 kJ = 8.36 kJ

Combining these values gives us qtotal = 0.339 kJ + 8.36 kJ = 8.70 kJ.

Now we can answer the question:

(a) False, AH refers to the heat capacity during melting.

(b) True, as we concluded earlier.

(c) False, there’s only one phase transition from solid (ice) to liquid.

(d) True based on our calculations above.

(e) False, according to our findings.

A mixture is created by dissolving 1.43 mol of potassium chloride (KCl) in 889 g of water. The concentration of KCl works out to be 1.61 molal.
The amount of KCl is 1.43 mol
Water weighs 889 g
The molality can be calculated using the formula:
molality = moles of solute divided by kilograms of solvent
Since 1 kg equals 1000 g, 889 g is 0.889 kg.

Therefore, m = 1.43/0.889 = 1.61 molal.