In order to use a pipet, place a ____________ at the top of the pipet. Use this object to fill the pipet such that the _________

Answer:- 64015 J

Solution: The calorimeter contains 4250 mL of water, which is at a temperature of 22.55 degrees Celsius.

The water's density is 1 gram per mL.

Thus, the mass of water = = 4250 grams.

After introducing the hot copper bar, the final temperature of the water reaches 26.15 degrees Celsius.

Thus, for the water = 26.15 - 22.55 = 3.60 degrees Celsius.

The specific heat capacity of water is 4.184 .

To determine the heat absorbed by the water, we can use the following formula:

where q represents heat energy, m refers to mass, and c indicates specific heat.

Now let's substitute the values into the equation to perform the calculations:

q = 64015 J

Therefore, the water absorbs 64015 J of heat.

Answer:

The particle's velocity is calculated to be 2 m/s,

Explanation:

Kinetic energy refers to the energy an object possesses due to its movement. The formula for kinetic energy is:

Where:

m = the mass of the object

v = the object's velocity

A particle with mass m has a kinetic energy that is double its mass.

Since the velocity is measured in m/s, we determine that the particle's speed is 2 m/s.

Wear gloves to avoid your nails from damaging the balloons due to their soft nature.

Answer: 0.0007 moles of are released when the temperature rises.

Explanation:

To determine the moles, we utilize the ideal gas law, as follows:

where,

P = gas pressure = 1.01 bar

V = gas volume = 1L

R = gas constant =

• Calculated moles at T = 20° C

The gas temperature = 20° C = (273 + 20)K = 293K

Substituting values into the equation gives:

• Calculated moles at T = 25° C

The gas temperature = 25° C = (273 + 25)K = 298K

Substituting values into the equation gives:

• Released moles =

Therefore, 0.0007 moles of are released when the temperature increases from 20° C to 25° C.

λ = h/p = h/mv; where λ represents the wavelength in meters, h denotes Planck's constant = 6.6261 × 10^-31 J/s, m symbolizes the mass (in kg), and v indicates the velocity in m/s.
The velocity is: 2.0 × 10^5 m/s
1 amu equals 1.66 × 10^-24 g
So, 19.992 amu translates to = 1.66 × 19.992 × 10^-24 g
 = 3.319 × 10^-23 g
Consequently; λ= (6.6261 × 10^-31)/(3.319×10^-23)×2×10^5)
     = 1.0 × 10^-13 m