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s344n2d4d5
3 days ago
9

A dog groomer is offering 20% off a full groom for one dog, and 15% off for each additional dog. You decide to take your two fur

ry friends to be groomed. Normally, a full groom costs $65 for each dog. Assuming there is no sales tax, what is the total discounted price for two dogs to be groomed? Report your answer to two decimal places. Do not include the dollar sign, $, in the answer box below.
Mathematics
1 answer:
zzz [9K]3 days ago
3 0

Answer: The total discounted cost to groom two dogs amounts to 22.75

Step-by-step explanation:

A grooming service is offering a 20% discount for the first dog and 15% off each subsequent dog. Typically, a full grooming service for one dog costs $65.

If you choose to groom both of your dogs,

the discount for the first one would be

20/100 × 65 = 0.2 × 65 = 13

the second dog's discount would be

15/100 × 65 = 0.15 × 65 = 9.75

Thus, the total discounted price for grooming the two dogs would be

13 + 9.75 = 22.75

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A salesperson earns $8 per hour plus 6% commission on her sales. In a week when she worked 40 hours, her total earnings were $69
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Answer:

6216.66

Detailed explanation:

(8*40)+6%*×=$692; 320 + 0.6x = 692; 0.6x=692-320; 0.6x=373; x=373÷0.6; x=6216.66

7 0
1 month ago
Complete the sentence below. If (3x2 + 22x + 7) ÷(x + 7) = 3x + 1, then (x + 7)(???????) =???? .
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Response: The outcome is (x+7)(3x+1)=33x^2+22x+7.

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(3x2 + 22x + 7) \div(x + 7) = 3x + 1,

we need to finalize the subsequent sentence:

(x+7)(???)=???

We have the polynomial division algorithm as follows

\textup{If }a(x)\times b(x)=c(x),\\\textup{then, we have }\\\\\dfrac{c(x)}{b(x)}=a(x)~~~~~\textup{or}~~~~~~c(x)\div b(x)=a(x).

In this equation, a(x) denotes the quotient, b(x) indicates the divisor, and c(x) stands for the dividend.

Using this principle in the current problem, it results in

\textup{since }(3x2 + 22x + 7) \div(x + 7) = 3x + 1,\\\\\textup{so, }\\\\(x+7)(3x+1)=3x^2+22x+7=0.

Consequently, the full sentence would be

(x+7)(3x+1)=3x^2+22x+7=0.

7 0
6 days ago
Read 2 more answers
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You might consider utilizing the following dataset:
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