Syd chooses two different primes, both of which are greater than $10,$ and multiplies them. The resulting product is less than $

Answer:

Hence, utilizing linear depreciation gives us 17222.22.

Step-by-step explanation:

The boat's initial value is noted to be $250,000.

The straight-line depreciation method for calculating a boat is as follows:

Cost of the boat is $250,000.

Deep Blue anticipates selling it for $95,000 after 9 years.

Employing the formula, we calculate:

(250000-95000)/9=155000/9=17222.22

Thus, the outcome using linear depreciation is 17222.22.

Response:  a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318

Detailed explanation:

In Problem 8-4, the computer time-sharing system experiences teleport inquiries at an average rate of 0.1 per millisecond. We are tasked with determining the probabilities of the inquiries over a specific period of 50 milliseconds:

Given that

Applying the Poisson process, we find that

(a) at most 12

probability=  

(b) exactly 13

probability=

(c) more than 12

probability=

(d) exactly 20

probability=

(e) within the range of 10 to 15, inclusive

probability=

Thus, a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318