7.35 moles of oxygen. Initially, for each mole of H₂CO₃, there are 3 moles of oxygen, as derived from the acid's formula. For 2.45 moles of the compound stated in the problem, which is carbonic acid, we calculate: If 1 mole of H₂CO₃ corresponds to 3 moles of oxygen, then for 2.45 moles of H₂CO₃, we have X moles of oxygen. Thus, X = (3 × 2.45) / 1 = 7.35 moles of oxygen.
What is being removed during the wash is the solvent.
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To determine the number of atoms present in 80.45 grams of magnesium, we require Avogadro's number and the weight of a single mole of magnesium.
Avogadro's number is 6.02 x 10^23 atoms, and the mass of one mole of magnesium is 24.31 grams.
1. First, divide by the weight of one mole of magnesium
80.45 / 24.31 ≈ 3.309 moles (rounded to appropriate significant figures)
2. Multiply the number of moles by Avogadro's number
3.309 x (6.02 x 10^23) ≈ 1.99 x 10^24 (rounded to appropriate significant figures)
Thus, in 80.45 grams of magnesium, there are approximately 1.99 x 10^24 atoms.
According to IUPAC guidelines, the primary carbon chain should have 9 carbon atoms, as indicated by the term 'nonane'. From this chain, two isopropyl groups (each with 3 carbon atoms) should be connected to the 4th and 5th carbons, starting from either end of the main carbon chain. The structural representation is displayed in the attached image.
