Sam needs to score 97 on his upcoming test to keep his average at 85. If you total 63, 84, 96, and 97, the sum is 340. Dividing 340 by four test scores yields an exact average of 85.
To find the maximum number of identical packs we see we have 72 pencils and 24 calculators.
This involves discovering the largest number that divides both 72 and 24 evenly,
which is known as the GCM or greatest common multiplier.
To determine the GCM, factor 72 into primes and group them:
72=2 times 2 times 2 times 3 times 3
24=2 times 2 times 2 times 3
Thus, the common grouping is 2 times 2 times 2 times 3, equating to 24.
Therefore, the maximum number of packs is 24.
For pencils:
72 divided by 24=3
Resulting in 3 pencils per pack.
For calculators:
24 divided by 24=1
So, 1 calculator per pack.
The outcome is 3 pencils and 1 calculator in each pack.
Response:
8861: 9495
Detailed explanation:
The income ratio for the years 2001 to 2003:
53,166: 56,970
To simplify, divide both sides by 6:
8,861: 9,495
This can't be simplified further, so that is the final result!
8861: 9495
I hope this helps! Have a great day:)
The diagrams for parts A and C are included here. For part B, we have circle O. We begin by drawing two radii OA and OC, connecting points A and C to create chord AC. The radius intersects chord AC at point B, bisecting AC into equal segments AB and BC. This gives us two triangles, ΔOBA and ΔOBC, where OA equals OC (since they're radii), OB equals OB (by the reflexive property), and AB is equal to BC (as stated in the question). By applying the SSS triangle congruence criterion, we conclude that ΔOBA is congruent to ΔOBC, allowing us to deduce that ∡OBA equals ∡OBC, both measuring 90°. Thus, OB is perpendicular to AC. Moving on to part D, we again work with circle O and draw the two radii OA and OC, joining points A and C to create chord AC. The radius intersects AC at point B, where AB is perpendicular to AC, meaning ∡B equals 90°. We then consider the right triangles ΔOBA and ΔOBC, and given OA equals OC (the radii), and OB equals OB (reflexive property), we conclude through the HL triangle congruence that ΔOBA is congruent to ΔOBC. Consequently, we find BA equal to BC, thus OB bisects AC.
<span>The admission price for the art museum is $9.75 per ticket.
</span><span>Compared to science museum tickets, art museum tickets are pricier.
</span>
This was verified through my testing.
