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2 months ago

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Insect Weights Consider a dataset giving the adult weight of species of insects. Most species of insects weigh less than 5 grams

, but there are a few species that weigh a great deal, including the largest insect known: the rare and endangered Giant Weta from New Zealand, which can weigh as much as 71 grams. Is the shape of the distribution symmetric, skewed to the right, or skewed to the left

1 answer:

babunello [11.8K]2 months ago

8 0

Response:

Detailed explanation:

Weighing 71 grams would certainly categorize as a high outlier, while the majority of insect species typically weigh significantly less. Consequently, this weight distribution's graph would be skewed to the lower end, or leftward.

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Carmen is planning rail lines for a new train station. Help her find m1. Explain how you found that solution.

tester [12383]

I have included a screenshot of the entire question along with its accompanying diagram.

Answer:
∠1 = 163°

Explanation:
1- finding angle 2:
Given that ∠2 together with 17° creates a straight angle, their total is 180°.
Thus:
180 = 17 + ∠2
Solving for ∠2 gives us:
∠2 = 180 - 17
∠2 = 163°

2- finding angle 1:
Since lines a and b are parallel, ∠1 and ∠2 are alternate angles and therefore equal.
We determined that ∠2 = 163°, leading to:
∠1 = 163°

I hope this clarifies things!:)

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3 months ago

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Zina [12379]

38 % of the total budget goes to advertising on broadcast TV

Solution:

Based on the details,

Expenditure for broadcast TV advertising = $ 22, 000

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Total expenditure = $ 58000

proportion of broadcast TV advertising = $\frac{\text{ amount spend on broadcast tv}}{\text{ total amount}} \times 100$

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Hence 38 % of the total budget is allocated to broadcast TV advertising

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2 months ago

The Spirit Team will be selling popcorn as a fundraiser at the next basketball game to earn funds to go to Orlando for a competi

zzz [12365]

Response:1 and 2

Step-by-step Explanation:

Provided data

Volume required $V=220\ in.^3$

For the initial cylinder

$r=3\ in.$

$h=4\ in.$

$V=\pi r^2h$

$V_1=\pi (3)^2(4)$

$V_1=113.11\ in^3$

For the second cylinder

$r=4\ in.$

$h=4\ in.$

$V=\pi r^2h$

$V_2=\pi (4)^2(4)$

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For the third cylinder

$r=9\ in.$

$h=9\ in.$

$V=\pi r^2h$

$V_3=\pi (9)^2(9)$

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For the fourth cylinder

$r=4\ in.$

$h=9\ in.$

$V=\pi r^2h$

$V_4=\pi (4)^2(9)$

$V_4=452.448\ in^3$

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3 months ago

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zzz [12365]

Answer:

$\$20,000$

Explanation step-by-step:

Let

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$1.05x=21,000$

To find x, divide both sides by 1.05:

$x=21,000/1.05$

$x=\$20,000$

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1 month ago