$38.00 imes 0.25 = $9.50
$38.00 - $9.50 = $28.75
$28.75 imes 0.06 = $1.725
$28.75 + $1.73 = $30.48
-10w - 400 = o
w= weeks
o = remaining balance
Response:
The probability that a student has a pet, given they do not have any siblings is:
Option: D ( 60%)
Step-by-step breakdown:
Let A represent the situation where a student lacks a sibling.
Let B signify the occurrence that a student has a pet.
Consequently, A∩B refers to the event in which a student is without siblings but possesses a pet.
Let P denote the chance of an event happening.
We need to determine:
P(B|A)
From our knowledge:

From the data provided:
P(A)=0.25
and P(A∩B)=0.15
Thus,

which expressed as a percentage is:

Therefore, the probability is:
60%
A(w) = -w² + 100w
Step-by-step explanation: Initially, we need to express the length (l) of the rectangular area in terms of the width (w). Given that the total perimeter of the rectangle is 200 feet implies that 2(w + l) = 200, leading to l = 100 - w. Hence, the area A can be given as width multiplied by length: A = w * l = w * (100 - w) = -w² + 100w. Consequently, A(w) = -w² + 100w.