answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
klasskru
1 month ago
12

Which environmental factor could lead to a decrease in genetic variation in a population of tuna? A.an increase in food availabi

lity B.an increase in pollution C.a decrease in tuna fishing D.a decrease in tuna predators
Chemistry
2 answers:
Alekssandra [3K]1 month ago
8 0
Hello! Your inquiry seeks to identify the environmental factor resulting in diminished genetic diversity within a tuna population. The accurate response is B: An increase in pollution.
KiRa [2.9K]1 month ago
6 0
An increase in pollution might lead to a decline in genetic variation within a tuna population.
You might be interested in
A decorative "ice" sculpture is carved from dry ice (solid CO2) and held at its sublimation point of –78.5°C. Consider the proce
lions [2927]

Answer:

The responses to the questions are:

a. The entropy of sublimation for CO2 is 134.07 J/Kmol.

b. The entropy for the universe in this reversible scenario is 376 J/K.

Explanation:

Entropy of sublimation refers to the change in entropy that occurs when one mole of a solid transitions to vapor at its sublimation point.

a. The mass of solid CO₂ is noted as 389 g.

The molar mass of CO₂ is 44.01 g/mol.

The number of moles of CO₂ in the sculpture is calculated as: Mass/(Molar mass)

= (389 g)/(44.01 g/mol) = 8.84 moles.

The entropy of sublimation is expressed as

ΔS_{sublimation} = S_{vapor} - S_{solid} = \frac{\Delta H_{sublimation}}{T}

Where:

ΔH_{sublimation}  = 26.1 KJ/mol.

T = Temperature = –78.5°C = ‪194.65‬ K.

Consequently, the energy required for the 389 g of dry ice to sublime is: 26.1 KJ/mol × 8.84 moles = 230.695 KJ.

Subsequently, the entropy of sublimation is calculated as ΔS_{sublimation} = \frac{230.695 KJ}{194.65 K}

= 1.185 KJ/K

= 1185 J/K = 1185/8.84 J/Kmol = 134.07 J/Kmol.

b. The universe’s entropy can be computed as:

ΔS_{universe} = \Delta S_{system} + ΔS_{surrounding}

If the heat absorbed by the system equals the heat released by the surroundings, then:

ΔS_{universe} = \frac{Q}{ T_{system}}  -\frac{Q}{T_{surrounding}}

                =1.185 KJ/K - -\frac{230.695 KJ}{285.15K} = 1.185 KJ/K - 0.809 KJ/K = 0.376 KJ/K

= 376 J/K.

7 0
2 months ago
2.00 liters of hydrogen, originally at 25.0 °C and 750.0 mm of mercury, are heated until a volume of 20.0 liters and a pressure
eduard [2782]

Response:  The updated temperature stands at 10643 K

Clarification:

The combined gas law integrates Boyle's law, Charles's law, and Gay-Lussac's law.

The equation for this law is given by:

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial gas pressure = 750.0 mm Hg = 0.98 atm   (760mmHg=1atm)

P_2 = final gas pressure = 3.50 atm

V_1 = initial gas volume = 2.00 L

V_2 = final gas volume = 20.0 L

T_1 = initial gas temperature = 25.0^oC=273+25.0=298.0K

T_2 = final gas temperature =?

Now substituting all the stated values into the equation, we obtain:

\frac{0.98\times 2.00}{298.0K}=\frac{3.50\times 20.0}{T_2}

T_2=10643K

Thus, the new temperature results in 10643 K

6 0
2 months ago
5. Gabi has plans with her friends to go to a concert on her birthday in 4 days. She is so excited that she wants to know how ma
Alekssandra [3086]
Consequently, she feels very anxious because she has 345600 seconds to wait. Explanation: 60 seconds make up 1 minute, and 60 minutes constitute an hour. Each hour has 3600 seconds (60*60) and 24 hours make up a day. Hence, 3600 seconds multiplied by 24 hours results in 1 day equating to 86400 seconds—therefore, over four days, we have 86400 * 4 equating to 345600.
7 0
1 month ago
Next we need to determine the mass of oleic acid in the monolayer. The concentration of the oleic acid/benzene solution is 0.02g
Alekssandra [3086]

Response:

m=1x10^{-6}g

Clarification:

Hello,

In this scenario, since a single drop equates to 0.05 mL of the solution provided, with a concentration of 0.02 g/mL, the mass of oleic acid in one drop calculates to:

m=0.02\frac{g}{L}*0.05mL*\frac{1L}{1000mL}\\ \\m=1x10^{-6}g

Best wishes.

3 0
3 months ago
Other questions:
  • How many carbon atoms are there in a 1.3-carat diamond? diamonds are a form of pure carbon. (1 carat?
    13·2 answers
  • How many grams of nano3 would you add to 500g of h2o in order to prepare a solution that is 0.500 molal in nano3?
    10·1 answer
  • When the temperature of an ideal gas is increased from 27C to 927C then kinetic energy increases by
    9·1 answer
  • Benzoic acid is in the process of being recrystallized. Your lab partner is in a hurry and after the impure benzoic acid is diss
    8·1 answer
  • The end point of a titration is defined as the volume of titrant added, while the equivalence point is the volume required for c
    9·1 answer
  • How many seconds are required to produce 4.00 g of aluminum metal from the electrolysis of molten alcl3 with an electrical curre
    14·1 answer
  • Challenge question: This question is worth 6 points. As you saw in problem 9 we can have species bound to a central metal ion. T
    7·1 answer
  • Assuming that the solubility of radon in water with 1 atm pressure of the gas over the water at 30 ∘C is 7.27×10−3M, what is the
    14·1 answer
  • Calculate the mass of hydrazine (N2H4) that contains a billion (1.000 x 10^9) hydrogen atoms.
    7·2 answers
  • Which sentences describe ponds and lakes?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!