The neutralization reaction that occurs between potassium hydroxide and sulfuric acid can be represented as follows
2KOH + H2SO4 ---> K2SO4 + 2H2O
The quantity of moles of KOH is calculated using (43.74 x 0.500)/ 1000 = 0.02187 moles
Given that the stoichiometric ratio of KOH to H2SO4 is 2:1, the moles of H2SO4 can be determined as 0.02187/2 = 0.01094 moles
To find the concentration (molarity), use the formula (0.01094/50) x 1000 = 0.2188M
Each molecule contains two of these ions
1 mole corresponds to 6.02 * 10^23 entities.
1 mole of (NH4)2S contains 2*6.02 * 10^23 ammonium ions (NH4+ in this instance) = 1.204 * 10^24 ammonium ions
5 moles of (NH4)2S accounts for 5 * 1.204*10^24 =
6.02 * 10^24 moles of NH4+ ions <<<<====Result
Answer:
C. strands of hair discovered at the scene.
Explanation:
By utilizing the strands of hair, you can retrieve the DNA of the individual involved. This will provide a clearer lead in resolving the case.
I hope this information is helpful....
Refer to the image for the answer. An aldehyde is a carbon chain that features a carbonyl group at its end, which is why it is termed aldehyde; if the carbonyl group is elsewhere on the chain, it’s referred to as a ketone. In this case, we have a 5-carbon aldehyde and the first carbon comprises the C=O group, the remaining four making up the chain. However, we must introduce a branched chain into the molecular formula. This means the longest chain cannot maintain a length of 5 carbons; instead, the maximum would be 4 carbons, making the additional carbon the branched unit. We can have two possibilities for the branched chain aldehyde with 5 carbons: one methyl group positioned at 2 and another at 3. Another potential aldehyde with branching cannot exceed 4 carbons as the longest; it must have a 3-carbon chain with 2 carbon radicals (methyl in this context). Thus, the three aldehydes with the specified formula and at least one branch can be represented, alongside their respective names in the attached image.
27g of sulfur divided by 32.065g per mole gives 0.84 moles.
13.4g of oxygen divided by 16g per mole gives 0.83 moles.
Take each of these results, divide by the smallest quantity, and round to the nearest whole number.
