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Strike441
1 month ago
7

Jenny multiplies the square root of her favorite positive integer by $\sqrt{2}$. Her product is an integer. a) Name three number

s that could be Jenny's favorite positive integer, and explain why each could possibly be Jenny's favorite integer. b) Suppose Jenny divides the square root of her favorite positive integer by sqrt(2). Does she have to get an integer? (Remember, when Jenny multiplies the square root of her favorite integer by sqrt(2), she gets an integer.)
Mathematics
1 answer:
tester [12.3K]1 month ago
4 0

Answer:Part a) 2,50,18

Part b) When Jenny divides the square root of her favorite positive integer by \sqrt{2}, the result is an integer.

Step-by-step explanation:

Let

x-------> the favorite positive integer

Part a)

1) For x=2

\sqrt{2}*\sqrt{2}=\sqrt{4}=2 -----> the product results in an integer

thus

The number x=2could potentially be Jenny's favorite positive integer

2) For x=50

\sqrt{50}*\sqrt{2}=\sqrt{100}=10 -----> the product results in an integer

thus

The number x=50could potentially be Jenny's favorite positive integer

3) For x=18

\sqrt{18}*\sqrt{2}=\sqrt{36}=6 -----> the product results in an integer

thus

The number x=18could potentially be Jenny's favorite positive integer

Part B)

1) For x=2

\sqrt{2}/\sqrt{2}=\sqrt{1}=1 -----> the outcome is an integer

2) For x=50

\sqrt{50}/\sqrt{2}=\sqrt{25}=5 -----> the outcome is an integer

3) For x=18

\sqrt{18}/\sqrt{2}=\sqrt{9}=3 -----> the outcome is an integer

Therefore

When Jenny divides the square root of her favorite positive integer by \sqrt{2}, she obtains an integer as a result.

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