Ask question

Ask question

All categories

12 days ago

7

Jenny multiplies the square root of her favorite positive integer by $\sqrt{2}$. Her product is an integer. a) Name three number

s that could be Jenny's favorite positive integer, and explain why each could possibly be Jenny's favorite integer. b) Suppose Jenny divides the square root of her favorite positive integer by sqrt(2). Does she have to get an integer? (Remember, when Jenny multiplies the square root of her favorite integer by sqrt(2), she gets an integer.)

1 answer:

tester [11.9K]12 days ago

4 0

Answer:Part a) $2,50,18$

Part b) When Jenny divides the square root of her favorite positive integer by $\sqrt{2}$ , the result is an integer.

Step-by-step explanation:

Let

x-------> the favorite positive integer

Part a)

1) For $x=2$

$\sqrt{2}*\sqrt{2}=\sqrt{4}=2$ -----> the product results in an integer

thus

The number $x=2$ could potentially be Jenny's favorite positive integer

2) For $x=50$

$\sqrt{50}*\sqrt{2}=\sqrt{100}=10$ -----> the product results in an integer

thus

The number $x=50$ could potentially be Jenny's favorite positive integer

3) For $x=18$

$\sqrt{18}*\sqrt{2}=\sqrt{36}=6$ -----> the product results in an integer

thus

The number $x=18$ could potentially be Jenny's favorite positive integer

Part B)

1) For $x=2$

$\sqrt{2}/\sqrt{2}=\sqrt{1}=1$ -----> the outcome is an integer

2) For $x=50$

$\sqrt{50}/\sqrt{2}=\sqrt{25}=5$ -----> the outcome is an integer

3) For $x=18$

$\sqrt{18}/\sqrt{2}=\sqrt{9}=3$ -----> the outcome is an integer

Therefore

When Jenny divides the square root of her favorite positive integer by $\sqrt{2}$ , she obtains an integer as a result.

You might be interested in

Find the value of x in the isosceles triangle shown below.

Leona [12105]

Solution:

x=8

Detailed explanation:

This isosceles triangle consists of two right triangles with sides equal to 8, $\sqrt{80}$ , and y

Considering we possess two sides of a right triangle, determining the third side can be achieved using the Pythagorean Theorem

$(\sqrt{80} )^2=8^2+y^2\\\\80=64+y^2\\\\y^2=16\\\\y=4$

Because it is an isosceles triangle, these two right triangles are the same, thus x=2y

Hence, x=2(4)=8

8 0

22 days ago

Read 2 more answers

Unlike most packaged food products, alcohol beverage container labels are not required to show calorie or nutrient content. An a

AnnZ [11902]

We determine that the true average calorie content as estimated in the sampled population surpasses the actual calorie content. Step-by-step explanation: An article discussed a pilot study where each of the 58 participants was asked to estimate the calorie count of a 12 oz beer known to have 153 calories. The observed sample mean of calorie estimation was 193, with a sample standard deviation of 88. Let $\mu$ = true average estimated calorie level within the sampled population. Thus, Null Hypothesis, : $\mu$ 153 calories {indicating that the true average estimated calorie content does not exceed the actual amount}. Alternative Hypothesis, $H_A$ : $\mu$ > 153 calories {indicating the true average estimation exceeds the actual}. The appropriate test statistic would be a one-sample t-test statistic, as we lack knowledge of the population standard deviation; Test Statistic = ~t = $t_n_-_1$

where, sample mean estimated calorie level = 193 calories, s = sample standard deviation = 88, and n = sample size = 58. Therefore, the test statistic = ~t = 3.462. The t-table indicates a critical value of 1.6725 for 57 degrees of freedom at a 0.05 significance level. Since our test statistic of 3.462 > 1.6725, we have sufficient evidence to reject the null hypothesis; thus, affirming that the true average estimated calorie content in the sampled population exceeds the real content.

8 0

6 days ago

A follow-up study will be conducted with a sample of 20 people from the 300 people who responded yes (support) and no (do not su

PIT_PIT [11918]

Response:

Detailed explanation:

Hello!

Stratified sampling involves the categorization of the population into subgroups based on pre-established criteria for the study. These subgroups consist of homogeneous units concerning the relevant characteristics. In this instance, individuals in the groups will represent only one of the two potential opinions (support or not support) and not both.

The researcher determines the sample size desired, considering several factors such as finances, material availability, and accessibility to experimental subjects (for instance, if they are endangered species, larger sample sizes may not be feasible).

One might conduct proportionate stratified sampling by selecting a proportion of respondents who answered "yes" along with those who answered "no."

In this sampling method, taking a specific proportion from each subgroup allows for a more straightforward extrapolation of results to the overall populations. For example, if you needed a sample size of n = 20, each stratum would ideally contain half, meaning 10 from the “yes” group and 10 from the “no” group.

I hope this is helpful!

4 0

1 month ago

The packaging process in a breakfast cereal company has been adjusted so that an average of 13.0 oz of cereal is placed in each

PIT_PIT [11918]

In order to determine this probability, we calculate using this difference: To obtain these probabilities, it’s possible to utilize normal standard distribution tables, a calculator, or software like Excel. The accompanying figure displays the results achieved. Here’s a detailed breakdown of the steps: Relevant concepts include the normal distribution, which describes a probability distribution that is symmetric regarding the mean, demonstrating that occurrences close to the mean are more likely than those farther away. The Z-score represents a statistical measure illustrating how far a value is from the average of a set, expressed in standard deviations. For our analysis, let X denote the random variable representing weights in a population, with its distribution characterized by: We’re specifically interested in this probability. The most effective approach to address this issue is through the standard normal distribution and the Z-score calculation, expressed as: Applying this formula to our probability provides the following: This allows us to calculate this probability with the provided difference: We use standard distribution tables, a calculator, or Excel for determining these probabilities. The graph illustrates the resulting outcome.

4 0

26 days ago

In a test of a printed circuit board using a random test pattern, an array of 16 bits is equally likely to be 0 or 1. Assume the

AnnZ [11902]

Answer:

A), B), and C) are clarified below.

Step-by-step explanation:

The inquiry involves using binary digits, employing probabilities that are equal for both conditions, by applying a random test pattern, where the formula is derived from p = q.

Simplifying gives us

P[k] = nCk / 2^n

A. Probability of all bits being 1s

16c16/2^16 = 1/65536

B. Probability of all bits being 0s

16c0/2^16 = 1/65536

C. The probability of having exactly 8 bits as 1s and the other 8 as 0s

16c8/2^16 = 12870/65536 => 0.1963 ≈ 19.63%

8 0

1 month ago