A town has a population of 14000 and grows at 3% every year. What will be the population after 6 years, to the nearest whole num
2 answers:
This scenario is similar to a compound interest problem where the following formula is utilized:
Here:
C is the principal amount
j stands for the interest rate
n represents the number of periods
M is the total amount
By applying this formula to our issue, we establish:
C equals the initial population
j indicates the annual growth rate
n corresponds to the years elapsed
M signifies the final population
Let's proceed with the calculations...
C = 14000
j = 3% = 3/100 = 0.03
n = 6
M =?
Substituting the known values and calculating gives us:
M = C.
M = 14000.
M = 14000.
M = 14000. 1.19
M = 16,716.7
Thus, the result is 16,717
:-)
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Let h signify the height of the tree.
Since ΔABC is similar to ΔADE, it follows that
DE/BC = AD/AB
This means that
h/1.94 = (5.1 + 10.2)/5.1 = 3
Consequently, h = 1.94*3 = 5.82 m
Final result: 5.82 m