A town has a population of 14000 and grows at 3% every year. What will be the population after 6 years, to the nearest whole num

Question

12 days ago

6

ber?

2 answers:

Zina [11.9K] · Answer 1 · 2026-03-28T01:48:05+03:00

This scenario is similar to a compound interest problem where the following formula is utilized:

$M = C. (1 + j)^{n}$

Here:

C is the principal amount

j stands for the interest rate

n represents the number of periods

M is the total amount

By applying this formula to our issue, we establish:

C equals the initial population

j indicates the annual growth rate

n corresponds to the years elapsed

M signifies the final population

Let's proceed with the calculations...

C = 14000

j = 3% = 3/100 = 0.03

n = 6

M =?

Substituting the known values and calculating gives us:

M = C. $(1 + j)^{n}$

M = 14000. $(1 +.03)^{6}$

M = 14000. $(1.03)^{6}$

M = 14000. 1.19

M = 16,716.7

Thus, the result is 16,717

:-)

zzz [11.8K] · Answer 2 · 2026-03-28T01:50:11+03:00

3 0

I think it's 16,700, but I could be wrong, so don't get upset if that is not the case. jhsksk