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11 days ago

AA3 +2=AAA CC6+6=CBB ABC=?

1 answer:

5 0

AA3 + 2 = AAA;

3 + 2 yields 5; - >> A = 5; thus, AAA equals 555. 

CC6 + 6 = CBB; 
6 + 6 gives 12; - >> B = 2; one unit moves to the left, converting C (1 +?) into B; and B has already been determined as 2; 

C = B-1, therefore 2-1 equals 1; - >>> C = 1; SVB computes to 122; 

To find ABC? - >> the answer is 521.

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The bus routes in a city run on average every 15 minutes. The route times can vary by three minutes. Which absolute value equati

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Response:

$Max = 18\ mins$

$Min = 12\ mins$

Step-by-step explanation:

Information given:

$Time = 15\ mins$

$Variation = 3\ mins$

Objective:

Calculate the maximum and minimum values

The max value is found as follows:

$Max = Time + Variation$

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The min value is identified as follows:

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step-by-step explanation:

When transversal l intersects lines m and n, the angles formed outside each line on the opposite side of the transversal constitute alternate angles (like ∠1 and ∠8). In contrast, alternate interior angles appear on opposite sides but are located between the two lines (like ∠3 and ∠6).

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Keywords: Transversal, angles

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12 days ago

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There are 345 students at a college who have taken a course in calculus, 212 who have taken a course in discrete mathematics, an

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Answer:

There are 369 students who enrolled in either calculus or discrete mathematics.

Step-by-step explanation:

I'll create a Venn diagram to illustrate these figures.

Let’s define:

A represents the count of students who completed calculus.

B stands for those who took discrete mathematics.

We have the following:

$A = a + (A \cap B)$

Here, a denotes the students who studied calculus exclusively, while $A \cap B$ represents those who took both subjects.

Using the same reasoning:

$B = b + (A \cap B)$

There are 188 students taking both calculus and discrete mathematics.

This implies that $A \cap B = 188$

A total of 212 students studied discrete mathematics.

<pBased on this, $B = 212$

345 students have attended a calculus course.

<pSo, from this information, $A = 345$

We find the total number of students who took either calculus or discrete mathematics.

$(A \cup B) = A + B - (A \cap B) = 345 + 212 - 188 = 369$

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Answer:

Step-by-step explanation:

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Answer:

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The sum of probabilities should be exactly 100%. When you add the probabilities of this distribution:

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The bars would fail to form a bell-shaped curve, confirming that this is not a normal distribution.

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6 days ago

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