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Rama09
12 days ago
9

Which equation can be used to find the length of Line segment A C? Triangle A B C is shown. Angle A C B is 90 degrees and angle

A B C is 40 degrees. The length of hypotenuse A B is 10 inches, the length of A C is b, and the length of C B is a. (10)sin(40o) = AC (10)cos(40o) = AC StartFraction 10 Over sine (40 degrees) EndFraction = AC StartFraction 10 Over cosine (40 degrees) EndFraction = AC

Mathematics
2 answers:
babunello [11.2K]12 days ago
5 0
a.) AC = (10)sin(40°). Hope this assists you!
zzz [11.8K]12 days ago
5 0
The equation to determine the length of line segment AC is AC = 10sin(40°).
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Calculating conditional probabilities - random permutations. About The letters (a, b, c, d, e, f, g) are put in a random order.
AnnZ [11894]

A="b is situated in the center"

B="c lies to the right of b"

C="The letters def occur sequentially in that arrangement"

a) b can occupy 7 positions; however, only one of these is the center. Therefore, P(A)=1/7

b) Let X=i; "b holds the i-th position"

Y=j; "c occupies the j-th position"

P(B)=\displaystyle\sum_{i=1}^{6}(P(X=i)\displaystyle\sum_{j=i+1}^{7}P(Y=j))=\displaystyle\sum_{i=1}^{6}\frac{1}{7}(\displaystyle\sum_{j=i+1}^{7}\frac{1}{6})=\frac{1}{42}\displaystyle\sum_{i=1}^{6}(\displaystyle\sum_{j=i+1}^{7}1)=\frac{6+5+4+3+2+1}{42}=\frac{1}{2}

P(B)=1/2

c) Let X=i; "d holds the i-th position"

Y=j; "e occupies the j-th position"

Let Z=k; "f is in the i-th position"

P(C)=\displaystyle\sum_{i=1}^{5}( P(X=i)P(Y=i+1)P(Z=i+2))=\displaystyle\sum_{i=1}^{5}(\frac{1}{7}\times\frac{1}{6}\times\frac{1}{5})=\frac{1}{210}\displaystyle\sum_{i=1}^{5}(1)=\frac{1}{42}

P(C)=1/42

P(A∩C)=2*(1/7*1/6*1/5*1/4)=1/420

P(B\cap C)=\displaystyle\sum_{i=1}^{3} P(X=i)P(Y=i+1)P(Z=i+2)\displaystyle\sum_{j=i+3}^{6}P(V=j)P(W=j+1)=\displaystyle\sum_{i=1}^{3}\frac{1}{6}\frac{1}{7}\frac{1}{5}(\displaystyle\sum_{j=1+3}^{6}\frac{1}{4}\frac{1}{3})=1/420

P(B∩A)=3*(1/7*1/6)=1/14

P(A|C)=P(A∩C)/P(C)=(1/420)/(1/42)=1/10

P(B|C)=P(B∩C)/P(C)=(1/420)/(1/42)=1/10

P(A|B)=P(B∩A)/P(B)=(1/14)/(1/2)=1/7

P(A∩B)=1/14

P(A)P(B)=(1/7)*(1/2)=1/14

Events A and B are independent

P(A∩C)=1/420

P(A)P(C)=(1/7)*(1/42)=1/294

Events A and C are not independent

P(B∩C)=1/420

P(B)P(C)=(1/2)*(1/42)=1/84

Events B and C are not independent

8 0
21 day ago
Rent for a 3-bedroom apartment is regularly 936 per month. Apartment management is now offering one month free for 12- month lea
babunello [11299]

Answer:

$858.

Detailed explanation:

The monthly rent for the 3-bedroom apartment is $936 under normal circumstances.

The landlord now provides one month free as part of a 12-month tenancy. Signing the lease means paying rent for only 11 months. Therefore, the total annual rent after applying this deal is:

\text{Rent of the apartment for 1 year after signing the lease}= 11\times 936

\text{Rent of the apartment for 1 year after signing the lease}= 10296

To find the adjusted monthly payment, divide the total amount $10,296 by 12 months.

\text{The new monthly amount}=\frac{10296}{12}

\text{The new monthly amount}=858

Hence, the revised monthly rent comes out to be $858.

8 0
1 month ago
Mike runs for the president of the student government and is interested to know whether the proportion of the student body in fa
zzz [11812]

Answer:

We conclude that less than or equal to 50% of the student body supports him significantly.

Step-by-step explanation:

Mike, while campaigning for the student government presidency, is keen to determine if more than 50% of the student body supports him.

A random sample of 100 students was surveyed, with 55 expressing support for Mike.

Let p = the proportion of students backing Mike.

Thus, Null Hypothesis, H_0: p \leq 50% {indicating that the proportion of supporters among the student body is significantly less than or equal to 50%}

Alternate Hypothesis, H_A: p > 50% {indicating that the proportion of supporters among the student body is significantly more than 50%}

The test statistics to be utilized here One-sample z proportion statistics;

T.S. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } ~ N(0,1)

where, \hat p = the sampled proportion in favor of Mike = \frac{55}{100} = 0.55

n = number of sampled students = 100

Therefore, test statistics = \frac{0.55-0.50}{\sqrt{\frac{0.55(1-0.55)}{100} } }

= 1.01

The z test statistic is 1.01.

At a significance level of 0.05, the z table provides a critical value of 1.645 for a right-tailed test.

Given that our test statistic falls below the critical value of z (1.01 < 1.645), we lack sufficient evidence to reject the null hypothesis as it remains outside the rejection region, leading to failure to reject our null hypothesis.

As a result, we conclude that less than or equal to 50% of the student body is in favor of him or the proportion supporting Mike is not significantly greater than 50%.

4 0
1 month ago
Write the number with the same value as 28 tens
zzz [11812]

It is understood that

One tens corresponds to the number -----------> 10

thus

28 tens translates to

28*10=280

hence

the result is

280


3 0
1 month ago
Read 2 more answers
Based on the graph shown to the right, whose phones cost varies directly with the amount of time spent talking?
Inessa [12133]

Answer:

B

Step-by-step explanation:

If two quantities have a direct variation, their graph will originate from the point of intersection at the origin.

Among all graphs, only Nikiya's intersects the origin, thus the answer is B.



8 0
1 month ago
Read 2 more answers
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