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2 months ago

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If the charge that enters each meter of the axon gets distributed uniformly along it, how many coulombs of charge enter a 0.100

mm length of the axon?

1 answer:

serg [3.5K]2 months ago

3 0

Answer:

The charge that enters a segment of axon measuring 0.100 mm is $8.98\times 10^{-12} C$

Explanation:

The electric field E produced at a certain point by a point charge is expressed as

$E=k \frac{q}{r^2}$

where $k$ represents the constant = $9.0 \times 10^9 Nm^2 / C^2$

$q$ denotes the point charge's magnitude, and $r$ is the distance from the point charge

The amount of charge entering one meter of the axon equals $5.\times 10^{11} \times (+e)$

The charge that enters a 0.100 mm length of the axon is $5.\times 10^{11} \times (+e) \times (0.1 \times 10^{-3}$

by substituting the value of $+e=1.6\times 10^{-19} C$ into the equation above, we find that the charge entering a 0.100 mm segment of the axon is

$q=5.\times 10^{11} \times1.6\times 10^{-19} \times (0.1 \times 10^{-3}\\q=8.98\times 10^{-12} C$

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3 months ago

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