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kvasek
4 days ago
13

You apply the brakes of your car abruptly and your book starts sliding off the front seat. Three observers sitting in the car ex

plain this differently. Observer A says that the book continued moving and the car accelerated from underneath it. Observer B says that the car pushed forward on the book. Observer C says that she must be in a noninertial reference frame because the book started moving without any extra objects interacting with it. Which of the observers is correct? Assume that the car is a frame of reference of all observers.
Physics
1 answer:
Softa [913]4 days ago
7 0

Answer:

All observers are accurate.

Explanation:

This situation reflects a matter of reference frames regarding the book's motion as perceived by different observers.

From their distinct frames of reference, each observer's perspective is valid.

Observer A is in an inertial reference frame.

Observers capable of explaining the book's behavior and its relationship to the car through the interplay of forces and changes in velocity are classified as being in inertial reference frames.

Observer A's observations illustrate this, for she pointed out the relative motion between the book and the car, indicating her position in an inertial reference frame.

Likewise, observers in these inertial reference frames can elucidate object velocity changes based on the forces affecting them from other objects.

This is exemplified by observer B, who notes the car's force impacting the book's velocity.

Observer C occupies a non-inertial reference frame, as Newton's laws of motion do not apply. This scenario arises within non-inertial frames.

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How do Red Ants and squirrels depend on plants​
ValentinkaMS [1149]

Red ants rely on plants since they inhabit some of them and they consume sweet substances, such as sugar that comes from sugarcane, while squirrels depend on plants for nuts that they eat.

5 0
15 days ago
Steel blocks A and B, which have equal masses, are at TA = 300 oC and T8 = 400 oC. Block C, with mc - 2mA, is at TC = 350 oC. Bl
serg [1198]

Answer:

b) TA = TB = TC

Explanation:

  • When the blocks are brought into contact and isolated from the environment, they will exchange heat until they achieve thermal equilibrium.
  • During this exchange, the hotter body will lose heat, which will be gained by the cooler body.
  • The equilibrium state will be established once this equation is satisfied:

       \Delta Q = c_{st}* m_{A} * (T_{fin} - T_{0A} ) = c_{st}* m_{B} * (T_{0B} - T_{fin} )

  • Substituting the initial temperatures T₀A = 300º C and T₀B = 400ºC, while simplifying for equal block masses mA = mB, enables us to solve for the final temperature, Tfin:

       (400 \ºC - T_{fin}) = (T_{fin} - 300 \ºC) \\ \\ 2* T_{fin} = 700\ºC\\ \\ T_{fin} = 350\ºC

  • At equilibrium, when both blocks combine, they will yield a uniform final temperature of 350ºC.
  • When block C, also at this temperature, makes contact, all three blocks will simultaneously reflect this final temperature of 350 ºC.
  • Therefore, option b) is correct.
8 0
6 days ago
Explain the challenges in developing an accurate rating system for earthquakes. What kinds of variables are there?
Yuliya22 [1153]

Answer:

The primary factors that influence the intensity of shaking during an earthquake include the depth of the quake, its distance from the fault line, the type of soil below, and specifics about the buildings—especially their height. We will focus on the last two (soil quality and structures) and their interaction.

6 0
1 day ago
A small box of mass m1 is sitting on a board of mass m2 and length L (Figure 1) . The board rests on a frictionless horizontal s
Ostrovityanka [942]

Explanation:

The entire system will accelerate due to the applied force. The box will feel a force opposing friction, and once this force surpasses the friction, the box will start moving. Therefore,

Ff = μs×m1×g

m1×a = μs×m1×g

a = μs×g

The force applied is expressed as

F = (m1 + m2)×a hence

F = μs×g×(m1+m2)

3 0
9 days ago
A nonlinear spring is used to launch a toy car. The car is pushed against the spring, compressing the spring 2.5 cm. The force t
serg [1198]

Answer:

1.56 J

Explanation:

According to the data provided,

the spring compression is x = 2.5 cm.

The force exerted by the spring is given by,

F = - k x

where k = 5000 N/m.

We want to find the potential energy stored.

Thus, the energy contained within the spring is

PE = \dfrac{1}{2}kx^2

PE = \dfrac{1}{2}\times 5000\times 0.025^2

PE = 1.56 J

Consequently, the energy stored in the spring amounts to 1.56 J.

5 0
10 days ago
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