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artcher
7 days ago
4

A gardener buys a rake and a pair of gloves for each 12 volunteers in the gardening club. Each pair of gloves cost$8.00. The gar

dener spends a total of $300 on both rakes and gloves. Form an equation with r, as the cost of one rake. Then solve the equation.
Question 1: What is the problem about?
Q2: What is the math information given to us?
Q3: What do you need to find(the equation) and answer it.
Show your work when finding the answer
Use a graph
Use a Chart/Table​

Mathematics
1 answer:
Svet_ta [11.2K]7 days ago
7 0
r = $17.00 To solve this, we set up the equation: 204 = 12r. Dividing both sides by 12 gives r = 204/12 = 17, meaning 12 fits into 204 exactly 17 times. The task involves determining the cost of one rake, denoted as r. Given that there are 12 volunteers and each has gloves costing $8.00 per pair, totalling $96.00, deducted from the $300 spent results in $204. The previous steps have solved the equation systematically.
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a homeowner wants to carpet two rooms that each measure 12 ft by 15 ft. how many square yards of carpet should be ordered
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12 days ago
5 Adoncia makes a scale drawing of the front of
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Answer:

Due to the drawing measuring 200 ft., which translates to 13.33 in. with a scale of 15 ft to 1 in., and given that the sheet of paper is 11 in. long, Adoncia's depiction will not fit onto the paper.

Step-by-step explanation:

The provided details include;

The scale is 15 ft = 1 in.

The actual monument's dimensions;

Height = 80 ft.

Length = 200 ft.

Hence, we can establish;

The necessary paper height = 80/15 = 16/3 = 5.33 in.

The necessary paper length = 200/15 = 40/3 = 13.33 in.

As the paper size provided is 11 in., which is standard at 8.5 in. by 11 in.,

The drawing length of 13.33 in. exceeds the available paper length of 11 in.

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24 days ago
In Gallup's Annual Consumption Habits Poll, telephone interviews were conducted for a random sample of 1,014 adults aged 18 and
babunello [10150]

Answer:

(b)E(x)=1.3087

(c)Variance of x =1.7119

(d)E(y)=2.0447

Step-by-step explanation:

The random variable x refers to the average number of cups of coffee consumed daily.

The total number of respondents equals 1014

(a) Probability distribution for x.

\left|\begin{array}{c|cccccc}x&0&1&2&3&4\\\\P(x)&\dfrac{365}{1014}&\dfrac{264}{1014}&\dfrac{193}{1014}&\dfrac{91}{1014}&\dfrac{101}{1014} \end{array}\right|

(b) Expected value for x

E(x)=\left(0\times\dfrac{365}{1014}\left)+\left(1\times\dfrac{264}{1014}\left)+\left(2\times\dfrac{193}{1014}\left)+\left(3\times\dfrac{91}{1014}\left)+\left(4\times\dfrac{101}{1014}\right)

E(x)=1.3087

(c) Variance for x

Variance =\sum (x-\mu)^2P(x)

\left|\begin{array}{c|cccccc}x&0&1&2&3&4\\(x-\mu)^2&1.7167&0.0953&0.4779&2.8605&7.2431\\\\P(x)&\dfrac{365}{1014}&\dfrac{264}{1014}&\dfrac{193}{1014}&\dfrac{91}{1014}&\dfrac{101}{1014} \\\\(x-\mu)^2P(x)&0.6179&0.0248&0.0910&0.2567&0.7215\end{array}\right|

Variance, \sum (x-\mu)^2P(x)=1.7119

(d)

\left|\begin{array}{c|cccccc}y&1&2&3&4\\\\P(y)&\dfrac{264}{649}&\dfrac{193}{649}&\dfrac{91}{649}&\dfrac{101}{649} \end{array}\right|

E(y)=\left(1\times\dfrac{264}{649}\left)+\left(2\times\dfrac{193}{649}\left)+\left(3\times\dfrac{91}{649}\left)+\left(4\times\dfrac{101}{649}\right)

E(y)=2.0447

The expected value for y surpasses that of x.

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21 day ago
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