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UkoKoshka
7 days ago
8

"A bottle of olive oil contains 1.4 qt of olive oil. What is that volume in milliliters?"

Mathematics
1 answer:
Leona [11K]7 days ago
3 0

Response:

The volume of oil in milliliters is 1,324.5.

Detailed explanation:

Volume of olive oil = 1.4 qt = 1.4 Quarts

And it is known that 1 Liter equals 1.057 Quarts.

1 L = 1.057 Quarts

Hence, 1.4 Quarts converts to:

1.4 Quarts=\frac{1.4}{1.057} L=1.3245 L

1 Liter corresponds to 1000 milliliters.

1 L = 1000 mL

1.3245 L=1.3245\times 1000=1,324.5 mL

Consequently, the volume of oil in milliliters equals 1,324.5.

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A ship sails at 15 miles per hour, while it can motor at 5 miles per hour. It sails for 6 hours to its destination but has to mo
tester [10659]

Greetings!

The conclusion is:

The return trip will take 18 hours.

Reasoning:

To determine the duration of the return journey, we must calculate the distance from the destination back to the starting point.

The ship travels at 15 miles per hour (mph) over 6 hours, yielding a distance of:

x=x_o+v*t\\\\x=0+15mph*6hours=90miles

The distance from the starting point to the destination is 90 miles, and for the return trip, the motor operates at a speed of 5 mph. Thus, computing the time taken gives us:

Distance=v*t\\\\t=\frac{Distance}{v}=\frac{90miles}{5mph}=18hours

Consequently, the return trip will take 18 hours to complete.

Have a nice day!

5 0
11 days ago
Mia had $22. Then she started to receive $4 a week as an allowance. She plans to save all of her money for a bicycle and draws a
AnnZ [10889]
For Mia's calculations, she should use y first because y signifies 22, while x indicates 4 dollars earned weekly.
8 0
17 days ago
Student researchers Haley, Jeff, and Nathan saw an article on the Internet claiming that the average vertical jump for teens was
tester [10659]

Answer:

At the α = 0.10 level, there is no substantial evidence indicating that the average vertical jump for students at this school differs from 15 inches.

Step-by-step explanation:

A hypothesis test is necessary to verify the assertion that the average vertical jump of students diverges from 15 inches.

The null and alternative hypotheses are:

H_0: \mu=15\\\\H_a: \mu\neq15

The significance level is set at 0.10.

The sample mean recorded is 17, and the sample standard deviation is 5.37.

The degrees of freedom are calculated as df=(20-1)=19.

The t-statistic is:

t_{19}=\frac{M-\mu}{s_M/\sqrt{n}} =\frac{17-15}{5.37/\sqrt{20}}=\frac{2}{5.37/4.47} =2/1.20=1.67

The two-tailed P-value corresponding to t=1.67 is P=0.11132.

<pSince this P-value exceeds the significance level, the result is not significant. Therefore, the null hypothesis remains unchallenged.

At the α = 0.10 level, there is no compelling evidence that the average vertical jump of students at this school deviates from 15 inches.

7 0
1 month ago
In triangle $abc$, $m\angle a = 90^\circ$, $m\angle b = 75^\circ$, and $bc = \sqrt {3}$ units. what is the area of triangle $abc
Inessa [11067]
Given the specified angles, one is 90 degrees, indicating that the triangle is a right triangle. With provided angles and one side representing the hypotenuse (the longest side), the area is determined using the formula: Area = 1/2 * base * height. Let's compute the height and base:

From sin 75, we derive height = 1.67.
And from cos 75, we obtain base = 0.45.

Calculating area gives us Area = (0.45 * 1.67) / 2, resulting in 0.37 square units.

Thus, the triangle's area is approximately 0.37 square units.
3 0
27 days ago
Find the values of x1 and x2 where the following two constraints intersect.
Inessa [11067]

Answer: x1 = 251/26, x2 = -111/26

Step-by-step explanation:

Greetings!

As illustrated in the diagram, the point you seek is where the two lines intersect.

This intersection point is found by solving the system of linear equations (both equations must be satisfied by the point):

9x_1 +7x_2=57\\4x_1 + 6x_2 = 13

You can approach solving it using the substitution method:

\text{solve for x1 in the first equation:}\\x_1 = \frac{1}{9}(57 - 7x_2)

Then substitute x1 into equation 2 to resolve x2:

\frac{4}{9}(57-7x_2) + 6x_2 = 13\\\text{doing the algebra you get:}\\x_2 = \frac{-111}{26}

After which, utilize the x2 value to establish x1:

x_1 = \frac{1}{9}(57 - 7x_2)= \frac{1}{9}(57 + 7*\frac{111}{26}) = 251/26\\

4 0
11 days ago
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