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Sveta_85
2 months ago
6

A ship sails at 15 miles per hour, while it can motor at 5 miles per hour. It sails for 6 hours to its destination but has to mo

tor on the return trip home. How long does it take for the return trip?
Mathematics
1 answer:
tester [12.3K]2 months ago
5 0

Greetings!

The conclusion is:

The return trip will take 18 hours.

Reasoning:

To determine the duration of the return journey, we must calculate the distance from the destination back to the starting point.

The ship travels at 15 miles per hour (mph) over 6 hours, yielding a distance of:

x=x_o+v*t\\\\x=0+15mph*6hours=90miles

The distance from the starting point to the destination is 90 miles, and for the return trip, the motor operates at a speed of 5 mph. Thus, computing the time taken gives us:

Distance=v*t\\\\t=\frac{Distance}{v}=\frac{90miles}{5mph}=18hours

Consequently, the return trip will take 18 hours to complete.

Have a nice day!

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Health inspector visits once a week.
Fire inspector comes every 12 days.

a) health inspector fire inspector.
day 7.                    day 12.   
day 14.                    day 24.
day 21.                    day 36.
day 28.                    day 48.
day 35.                    day 60.

b) 12 x 7 = 84.

Both will coincide on day 84.




6 0
2 months ago
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Justin’s financial goal is to purchase a home. Which sentence describes how Justin could make his goal measurable and timely?
PIT_PIT [12445]
The answer is c Step-by-step explanation:
7 0
2 months ago
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Leslie determined that the system of equations below has infinitely many solutions. Is she correct?
tester [12383]

Respuesta:

Leslie determinó que el siguiente sistema de ecuaciones tiene infinitas soluciones. ¿Está en lo correcto?

x=4y-4

2x-8y=-24

A. Sí, Leslie está en lo correcto.

B. No, la solución es (-8,-24)

C. No, la solución es (0,-16)

D. No, el sistema de ecuaciones no tiene solución.

Explicación paso a paso:

debes resolverlo como un par de ecuaciones simultáneas y no hay soluciones

si necesitas una explicación más detallada, vuelve a publicar la pregunta y lo haré con gusto

por favor márcalo como el más útil


6 0
1 month ago
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Albert Abbasi, VP of Operations at Ingleside International Bank, is evaluating the service level provided to walk-in customers.
babunello [11817]

Answer:

The likelihood that Albert's sample of 64 will have a mean waiting time between 13.5 and 16.5 minutes is 0.9973.

Step-by-step explanation:

Prior concepts

A normal distribution is characterized as a "probability distribution that is symmetric around the mean, indicating that data close to the mean are more frequent than those further away".

The Z-score refers to "a statistical measurement that reflects the relationship of a value to the mean of a group, measured in standard deviations".

Let X denote the random variable of interest, and we identify its distribution:

X \sim N(\mu=15,\sigma=4)

Also, let \bar X signify the sample mean, whose distribution is:

\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})

In this case, \bar X \sim N(15,\frac{4}{\sqrt{64}})

Solution to the problem

We seek this probability

P(13.5

Applying the Z-score formula to the probability results in:

P(13.5

=P(\frac{13.5-15}{\frac{4}{\sqrt{64}}}

To determine these probabilities, we can refer to normal distribution tables, use Excel, or a calculator.

P(-3

The likelihood that Albert's sample of 64 will have a mean waiting time between 13.5 and 16.5 minutes is 0.9973.

7 0
1 month ago
Another project on Kickstarter for an iPad stylus raised 1,253% of their goal, raising a total of $313,490 from 7,511 supporters
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Answer:

The initial goal was $25019.154.

Step by step Explanation:

Assuming the original goal is denoted as x.

As stated

Another Kickstarter initiative for an iPad stylus secured 1,253% of its target, accumulating a total of $313,490.

1253% can be expressed as a decimal.

= \frac{1253}{100}

= 12.53

Thus, the equation is rearranged to

12.53 × x = 313490

12.53x = 313490

x = \frac{313490}{12.53}

x = $ 25019.154

This means the initial goal stands at $25019.154.

8 0
2 months ago
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