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dedylja
1 month ago
15

Plutonium isotopes undergo decay, producing heat. Plutonium isotope 239 (Pu-239) has 1.9 watts per kilogram [W/kg] of decay heat

. How much heat, in units of calories [cal], will 1.25 moles [mol] of Pu-239 release after decaying for three hours [h]
Engineering
1 answer:
Daniel [329]1 month ago
7 0
The result is 1495.81 calories, which rounds to 1500 calories at 2 significant figures.

Explanation: For each kilogram of Pu-239 decaying, there is a decay heat release of 1.9 Watts. To find the heat released by 1.25 moles of Pu-239 over a duration of 3 hours (in calories): First, we find the mass of Pu-239 in 1.25 moles. The molar mass of Pu-239 is 244 g/mol or 0.244 kg/mol. Thus, 1.25 moles = 1.25 × 0.244 = 0.305 kg. Each kilogram yields 1.9 Watts, hence: 0.305 kg of Pu-239 results in (0.305 × 1.9) Watts; approximately 0.5795 Watts. Note that Watts equate to J/s. Using the relation Power = Energy/time, we have Energy = power × time. Knowing: Power = 0.5795 Watts, Time = 3 hours = 10800 seconds, we calculate: Energy = 0.5795 × 10800 = 6258.6 J. Finally, converting to calories: 6258.6 J equals 1495.81 calories when multiplied by 0.239, thus reaching the total of approximately 1495.81 calories.

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Water flows steadily through a horizontal nozzle, discharging to the atmosphere. At the nozzle inlet the diameter is D1; at the
mote1985 [299]
The inlet gauge pressure must be 61.627 Psi.
4 0
2 months ago
A 90-hp (shaft output) electric car is powered by an electric motor mounted in the engine compartment. If the motor has an avera
pantera1 [306]

Answer:

Heat supply rate is measured at 8.901 horsepower.

Explanation:

Energy efficiency of the electric vehicle, as per Thermodynamics (\eta), is the proportion of translational mechanical power (\dot E_{out}), expressed in horsepower, and electrical energy (\dot E_{in}), also in horsepower. The heat supply rate (\dot E_{l}), indicated in horsepower, that the motor delivers to the engine bay under full load can be determined by subtracting the translational mechanical energy from the electric energy. This is expressed as:

\eta = \frac{\dot E_{out}}{\dot E_{in}} (1)

\dot E_{l} = \dot E_{in}-\dot E_{out} (2)

\dot E_{l} = \left(\frac{1}{\eta}-1\right)\cdot \dot E_{out} (3)

If we have the values of \eta = 0.91 and \dot E_{out} = 90\,hp, the heat supply rate can be calculated as:

\dot E_{l} = \left(\frac{1}{0.91}-1 \right)\cdot (90\,hp)

\dot E_{l} = 8.901\,hp

The heat supply rate amounts to 8.901 horsepower.

4 0
2 months ago
Compute the sum with carry-wraparound (sometimes called the one's complement sum) of the following two numbers. Give answer in 8
grin007 [323]

Response:

00100111

Explanation:

We have been given;

10010110

10010000

Add them following standard binary addition rules

10010110

10010000

-------------

(1)00100110

-------------

ignore the leading (1) because it is a carry.

Increase the result by 1 to achieve a 1's complement sum

00100110 + 1 = 00100111

Final Result: 00100111

3 0
2 months ago
A hydraulic cylinder is to be used to move a workpiece in a manufacturing operation through a distance of 50 mm in 10 s. A force
Viktor [391]

Response:

The solution to this question is 1273885.3 ∅

Clarification:

The first step is to ascertain the required hydraulic flow rate liquid based on the working pressure if a cylinder with a piston diameter of 100 mm is utilized.

Given that,

The distance = 50mm

The time t =10 seconds

The force F = 10kN

The piston diameter = 100mm

The pressure = F/A

10 * 10^3/Δ/Δ

P = 1273885.3503 pa

Subsequently

Power = work/time = Force * distance /time

= 10 * 1000 * 0.050/10

which amounts to =50 watt

Power =∅ΔP

50 = 1273885.3 ∅

5 0
1 month ago
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