The 10-kg block slides down 2 m on the rough surface with kinetic friction coefficient μk = 0.2. What is the work done by the fr
iction force?
1 answer:
Answer:
153.2 J
Explanation:
Let’s first identify our known variables:
mass (m) of the block = 10 kg
distance slid down (i.e., displacement) = 2 m
coefficient of kinetic friction (μk) = 0.2
In the following diagram, if we analyze the force component directed along the displacement, we find
Fcos 40°
100 (cos 40°)
76.60 N
The work done by the frictional force is then calculated as:
W = × displacement
W = 76.60 × 2
W = 153.2 J
Therefore, the work done by the frictional force equals 153.2 J
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Answer:
Refer to the attached document
1512 ft
Explanation:
Because the acceleration is constant or zero, the acceleration-time graph consists of horizontal segments. The values for t2 and a4 are derived as follows:
Acceleration - Time
0 < t < 6: Velocity change = area beneath the a–t graph
V_6 - 0 = (6 s)(4 ft/s²) = 24 ft/s
6 < t < t2: The velocity rises from 24 to 48 ft/s,
Velocity change = area beneath the a–t graph
48 - 24 = (t2 - 6) * 6
t2 = 10 s
t2 < t < 34: The velocity remains constant, meaning acceleration is zero.
34 < t < 40: Velocity change = area beneath the a–t graph
0 - 42 = 6*a4
a4 = - 8 ft / s²
A negative acceleration shows the area lies below the t-axis, indicating a decrease in speed.
Velocity - Time
Since acceleration remains constant or zero, the v−t graph is made up of linear segments connecting the calculated points.
Position change = area beneath the v−t graph
0 < t < 6: x6 - 0 = 0.5*6*24 = 72 ft
6 < t < 10: x10 - x6 = 0.5*4*(24 + 48) = 144 ft
10 < t < 34: x34 - x10 = 48*24 = 1152 ft
34 < t < 40: x40 - x34 = 0.5*6*48 = 144 ft
Summing these position changes yields the distance from A to B:
d = x40 - 0 = 1512 ft
Response:
The cutting speed is calculated at 365.71 m/min
Clarification:
Given parameters include
diameter D = 250 mm
length L = 625 mm
Feed f = 0.30 mm/rev
cut depth = 2.5 mm
n = 0.25
C = 700
To find
the cutting speed that ensures the tool life coincides with the cutting time for the three parts
The formula for cutting time is given as
Tc =
....................1where D refers to diameter, L refers to length and f refers to feed while V represents speed
Tc =
Tc =
Given the tool life is expressed as
T = 3 × Tc............................2
where T denotes tool life and Tc is the cutting duration
Calculating tool life by substituting values into equation 2 yields
T = 3 ×
This yields V = 365.71
Thus, the cutting speed calculates to 365.71 m/min
Response:
a) 144.000 seconds
b) and c) Battery voltage and power graphs are in the attached image.
where D:{0<t h="" />
d) 1620 J
Description:
a) The initial response is derived via a rule of three
b) Using the line equation from the starting point (0 seconds, 1.5 V)
where m denotes the slope.
where V represents voltage in volts and t signifies time in seconds
along with P and m.
d) By evaluating that count.
