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22 days ago

Which summation formula represents the series below? 13 + 9 + 5 + 1

Mathematics

2 answers:

Leona [9.2K]22 days ago

8 0

Answer:

$\sum_{x=1}^{4}(17-4n)$

Step-by-step explanation:

The expression in question is

$13+9+5+1$

The series consists of the following terms

13,9,5,1

This is an arithmetic progression (AP). The first term here is 13, and the common difference is -4.

The nth term formula for an AP is

$a_n=a+(n-1)d$

where a represents the first term and d is the common difference.

The nth term of the AP defined here is

$a_n=13+(n-1)(-4)$

$a_n=13-4n+4$

$a_n=17-4n$

The formula for summation of an AP is

$\sum_{x=1}^{n}a_n$

The total number of terms is 4, thus, the summation formula can be stated as

$\sum_{x=1}^{4}(17-4n)$

AnnZ [9K]22 days ago

5 0

$13 + 9 + 5 + 1 = 27$

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26 days ago

In the figure, CD = EF and AB = CE. Complete the statements to prove that AB = DF.

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Answer:

1. Addition Property of Equality

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Step-by-step explanation:

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To Show: AB = DF

Following the steps outlined:

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This shows that the same value has been added to both sides of the equation.

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1 month ago

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Triangle QRS is a right triangle with the right angle at vertex R. The sum of m∠Q and m∠S must be equal to 45°. greater than 45°

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Answer:

The angles m∠Q and m∠S together equal 90°

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A right angle measures 90°.

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25 days ago

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1 month ago

Given matrix A below, and that A = B, find the value of the elements in B. A = 9 −2 3 2 17 0 3 22 8 b11 = b12 = b13 = b21 = b22

Svet_ta [9500]

Answer:

$b_{11}=9,b_{12}=-2,b_{13}=3,b_{21}=2,b_{22}=17,b_{23}=0,b_{31}=3,b_{32}=22,b_{33}=8$

Step-by-step explanation:

Review the provided matrix

$A=\left[\begin{array}{ccc}9&-2&3\\2&17&0\\3&22&8\end{array}\right]$

Let matrix B be defined as

$B=\left[\begin{array}{ccc}b_{11}&b_{12}&b_{13}\\b_{21}&b_{22}&b_{23}\\b_{31}&b_{32}&b_{33}\end{array}\right]$

It is stated that

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$\left[\begin{array}{ccc}9&-2&3\\2&17&0\\3&22&8\end{array}\right]=\left[\begin{array}{ccc}b_{11}&b_{12}&b_{13}\\b_{21}&b_{22}&b_{23}\\b_{31}&b_{32}&b_{33}\end{array}\right]$

By comparing the corresponding elements from both matrices, we derive

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$b_{31}=3,b_{32}=22,b_{33}=8$

Consequently, the needed values are $b_{11}=9,b_{12}=-2,b_{13}=3,b_{21}=2,b_{22}=17,b_{23}=0,b_{31}=3,b_{32}=22,b_{33}=8$ .

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