The image of ΔABC after a reflection across Line E G is ΔA'B'C'. 2 triangles are shown. A line of reflection is between the 2 tr

Answer: The correct choice is (C) A = {1, 2, 3, 4, 5, 7, 8}.

Step-by-step explanation: We have eight identical slips of paper, each numbered from one to eight, which have been mixed inside a bag.

The sample space, S is as follows:

S = {1, 2, 3, 4, 5, 6, 7, 8}.

Subset A consists of the complement of the event where the number 6 is drawn.

Let 'B' denote the event of drawing the number 6.

Thus, B = {6}.

Since 'A' represents the complement of 'B', it will include all elements in the sample space 'S' that are not part of set 'B'.

Therefore,

A = B' = {1, 2, 3, 4, 5, 7, 8}

So, A = {1, 2, 3, 4, 5, 7, 8}.

Consequently, (C) is the correct choice.

Answer:

Michael purchases 60 kg of dark chocolate alongside 40 kg of milk chocolate.

Step-by-step explanation:

Let d signify the kilograms of dark chocolate bought by Michael and m signify the kilograms of milk chocolate he acquires.

He must acquire a total of 100 kg of chocolate, thus

With dark chocolate priced at $12 per kg, the cost for d kg would be $12d. The price of milk chocolate is $10 per kg, indicating the cost for m kg is $10m. Michael intends to spend $1,120 on the chocolate, therefore

Taking the first equation

By inserting this into the second equation:

Michael ends up buying 60 kg of dark chocolate and 40 kg of milk chocolate.

Answer:

You need to purchase 3 shirts to be able to use your coupon.

Step-by-step explanation:

Each shirt originally costs $17.99.

There is a 20% discount on this specific brand of shirts.

$17.99 × 0.2 = $3.60 (discount per shirt)

Subtracting the discount from the original price:

$17.99 - $3.60 = $14.39 (price per shirt after discount)

To qualify for the $10 off coupon which requires a $40 minimum purchase:

$40 ÷ $14.39 ≈ 2.779, rounded up to 3 shirts

Therefore, you must buy 3 shirts.

3 shirts × $14.39 = $43.17, surpassing the $40 minimum needed to apply the $10 discount.

Answer:

Here is the solution to the entire assessment: https://school.ckseattle.org/documents/2019/2/8_2_The_Pythagorean_Theorem_and_Its_Converse.pdf

Step-by-step explanation: