Given matrix A below, and that A = B, find the value of the elements in B. A = 9 −2 3 2 17 0 3 22 8 b11 = b12 = b13 = b21 = b22

Question

erik

8 days ago

12

Given matrix A below, and that A = B, find the value of the elements in B. A = 9 −2 3 2 17 0 3 22 8 b11 = b12 = b13 = b21 = b22

= b23 = b31 = b32 = b33 =

Mathematics

2 answers:

Inessa [3.9K] · Answer 1 · 2026-02-25T06:12:53+03:00

Inessa [3.9K]8 days ago

5 0

Response:

b11 =

9

b12 =

-2

b13 =

3

b21 =

2

b22 =

17

b23 =

0

b31 =

3

b32 =

22

b33 =

8

Svet_ta [4.3K] · Answer 2 · 2026-02-25T06:11:21+03:00

Svet_ta [4.3K]8 days ago

3 0

Answer:

$b_{11}=9,b_{12}=-2,b_{13}=3,b_{21}=2,b_{22}=17,b_{23}=0,b_{31}=3,b_{32}=22,b_{33}=8$

Step-by-step explanation:

Review the provided matrix

$A=\left[\begin{array}{ccc}9&-2&3\\2&17&0\\3&22&8\end{array}\right]$

Let matrix B be defined as

$B=\left[\begin{array}{ccc}b_{11}&b_{12}&b_{13}\\b_{21}&b_{22}&b_{23}\\b_{31}&b_{32}&b_{33}\end{array}\right]$

It is stated that

$A=B$

$\left[\begin{array}{ccc}9&-2&3\\2&17&0\\3&22&8\end{array}\right]=\left[\begin{array}{ccc}b_{11}&b_{12}&b_{13}\\b_{21}&b_{22}&b_{23}\\b_{31}&b_{32}&b_{33}\end{array}\right]$

By comparing the corresponding elements from both matrices, we derive

$b_{11}=9,b_{12}=-2,b_{13}=3$

$b_{21}=2,b_{22}=17,b_{23}=0$

$b_{31}=3,b_{32}=22,b_{33}=8$

Consequently, the needed values are $b_{11}=9,b_{12}=-2,b_{13}=3,b_{21}=2,b_{22}=17,b_{23}=0,b_{31}=3,b_{32}=22,b_{33}=8$ .