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boyakko
1 month ago
8

A campus deli serves 300 customers over its busy lunch period from 11:30 a.m. to 1:30 p.m. A quick count of the number of custom

ers waiting in line and being served by the sandwich makers shows that an average of 10 customers are in process at any point in time.Round your answer to 3 digits after the decimal point if it is not an integer. Do NOT use comma in your numeric answers.
Mathematics
1 answer:
zzz [12.3K]1 month ago
3 0
In summary: A deli on campus serves 300 customers during lunchtime from 11:30 a.m. to 1:30 p.m. A quick count shows an average of 10 customers being served or waiting at any moment. What is the typical time a customer spends being served? The answer is 4 minutes. Explanation: We apply Little's law here, which relates the average number of items in a steady queuing system to the average waiting time and the flow rate of items entering the system. The formula states: Inventory = flow rate × flow time. Given the inventory is 300 customers, the flow time is 120 minutes (2 hours), and thus the flow rate is 300/120 = 2.5 persons per minute. Given that we know 10 customers are in process at a time, the average flow time works out to be 10/2.5 = 4 minutes.
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Answer:

The price per kilogram of salami amounts to = $9.1

Step-by-step explanation:

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10 times as many as blank hundreds or 60 hundreds is blank thousands
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The result of multiplying 10 by 6 hundreds equals 60 hundreds, which can also be expressed as 6 thousands.

Explanation

This can be simplified as follows:

  • 10 times a given quantity of _____ hundreds results in 60 hundreds
  • 60 hundreds convert to _____ thousands

We will divide this into two segments:

\boxed{ \ 10 \times (N \times 100) = 60 \times 100 \ }... Equation-1

\boxed{ \ 60 \times 100) = M \times 1,000 \ }... Equation-2

This straightforward multiplication relates to the place value system. We need to perform calculations to find the values of N and M.

Initially, let's focus on Equation-1.

We will move the variable M to one side of the equation in order to isolate it and solve for its value.

\boxed{ \ 10 \times (N \times 100) = 60 \times 100 \ }

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Both parts will be divided by 1,000, essentially being multiplied by \frac{1}{1,000}.

\boxed{ \ \frac{1}{1,000} \times 1,000 \times N = \frac{1}{1,000} \times 6,000 \ }

Thus, we conclude with \boxed{\boxed{ \ N = 6 \ }}

Next, we process Equation-2 to derive M's value.

\boxed{ \ 60 \times 100) = M \times 1,000 \ }

\boxed{ \ 6,000 = M \times 1,000 \ }

Rearranging this equation to place M on the left side appears as follows:

\boxed{ \ M \times 1,000 = 6,000 \ }

Again, both sides undergo division by 1,000, which translates to multiplication by \frac{1}{1,000}..

\boxed{ \ \frac{1}{1,000} \times M \times 1,000 = \frac{1}{1,000} \times 6,000 \ }

This results in \boxed{\boxed{ \ M = 6 \ }}

- - - - - - -

Alternative approach for the second step:

60 hundreds equals to __ thousands

\boxed{ \ 6 \times 10 \ hundreds = \ M \ thousands} \ }

\boxed{ \ 6 \times thousands = \ M \ thousands} \ }

\boxed{\boxed{ \ M = 6 \ }}

Additional resources

  1. A more detailed version of this topic
  2. 2 thousands 7 tens divided by 10 equals what?
  3. 100 is equivalent to 1/10 of which number?

Keywords: 10 times as many as, blank, hundreds, 60 hundreds, or, thousands, isolate, operations, multiply, divide, fraction, both sides, equal, the opposite, both sides are multiplied by, divided by, rearrange

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