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puteri
2 months ago
8

Does a fish appear closer or farther from a person wearing swim goggles with an air pocket in front of their eyes than the fish

really is? Does the fish see the person's face closer or farther than it really is? Explain your answer.
Physics
1 answer:
Sav [3.1K]2 months ago
4 0

Response:

In this scenario, the refractive index of seawater is 1.33, while the index for air is 1. Because of this, the refraction angle is smaller than the angle of incidence, making the fish appear closer

Conversely, when viewed from the fish's perspective looking at a person's face, the angle has increased, making the person appear further away

Clarification:

This discussion is analyzed by applying the refraction law, which states that when a light ray crosses from one medium to another, its path bends due to differing indices of refraction,[ [TAG_20]]

n₁ sin θ₁ = n₂ sin θ₂

where n₁ and n₂ are the refractive indices and θ represents the angles for each medium.

Here, with seawater being 1.33 and air at 1, the refraction angle remains lesser than the angle of incidence, leading to the fish appearing nearer

1 sin θ₁ = 1.33 sin θ₂

θ₂ = sin⁻¹ ( 1/1.33 sin θ₁)

When the fish gazes at the human face, the angle's reason increases, hence making the face seem more distant

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If a metal wire is 4m long and a force of 5000n causes it to stretch by 1mm, what is the strain?
serg [3582]

Answer:

2.5\cdot 10^{-4}

Explanation:

Strain is defined as the ratio of an object's dimensional change when subjected to a force:

S=\frac{\Delta L}{L_0}

where

\Delta L indicates the alteration in length of the object

L_0 signifies the object's initial length

In this case, we have L_0 = 4 m and \Delta L=1 mm=0.001 m, hence the strain is

S=\frac{\Delta L}{L_0}=\frac{0.001 m}{4 m}=2.5\cdot 10^{-4}


5 0
2 months ago
Kai takes a hamburger off of the grill and puts a piece of cheese on it. Explain how and why the cheese melts when Kai puts it o
Keith_Richards [3271]
When Kai removes the burger from the grill and adds cheese, the cheese melts due to the heat retained by the burger from cooking. The warmth remains in the burger for a while, which explains the melting of the cheese.
4 0
2 months ago
Read 2 more answers
A truck collides with a car on horizontal ground. At one moment during the collision, the magnitude of the acceleration of the t
inna [3103]

Response:

The car's acceleration magnitude is 35.53 m/s²

Details:

Given;

acceleration of the truck, a_t = 12.7 m/s²

mass of the truck, m_t = 2490 kg

mass of the car, m_c = 890 kg

let the acceleration of the car during the collision = a_c

Using Newton's third law of motion;

The force exerted by the truck equals the force exerted by the car.

The car's force acts in the opposite direction.

F_c = -F_t\\\\m_ca_c = -m_t a_t\\\\a_c =- \frac{m_ta_t}{m_c} \\\\a_c = -\frac{2490 \times 12.7}{890} \\\\a_c = - 35.53 \ m/s^2

Thus, the car's acceleration magnitude is 35.53 m/s²

3 0
3 months ago
Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of
inna [3103]

Answer:

\int\limits^2_0 {} \, \int\limits^{5\pi}_0 {F(S(u,v)).N} \,dvdu ≈ 3077.34

Explanation:

To calculate the flux of F (vector field) across surface S, where

F(x,y,z) = y i − x j + z^{2} k

and S(u,v) = u cos v i + u sin v j + v k, 0 ≤ u ≤ 2, 0 ≤ v ≤ 5π

We will evaluate the following integral:

\int\limits^2_0 {} \, \int\limits^{5\pi}_0 {F(S(u,v)).N} \,dvdu

Substituting for the surface

x = u cos v

y = u sin v

z = v

Then

F(S(u,v)) = u sin v i - u cos v j + v^{2}k

The normal vector N is computed as

N = S_{u}XS_{v}

Where:

S_{u} = =

S_{v} = =

N = < cos v, sin v, 0 > X <- u sin v, u cos v, 2v

N = < 2v sin v, -2v cos v, u >

F(S(u,v)).N = < u sin v, -u cos v, v^{2}>. < 2v sin v, -2v cos v, u >

F(S(u,v)).N = 2uv + uv^{2}

Thus

\int\limits^2_0 {} \, \int\limits^{5\pi}_0 {2uv}+u v^{2}\,dvdu ≈ 3077.34

8 0
2 months ago
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