The following items are connected in a circuit. in which one would you find a voltage gain?

The energy difference between the 5d and the 6s sublevels in gold accounts for its color. If this energy difference is about 2.7

Yuliya22 [3333]

The light's wavelength absorbed during the transition is 459 nm. Energy difference between the 5-d and the 6-s sub-levels in gold is expressed as ΔE. Let the wavelength associated with the electron's transition from the 5-d to the 6-s state be λ. The relationship that describes the connection between energy and wavelength is defined as: E = hc/λ, where E stands for photon energy, h represents Planck's constant, c is the speed of light, and λ denotes the wavelength of the photon. Therefore, the absorption wavelength in this transition stands at 459 nm.

8 0

2 months ago

A 17 g audio compact disk has a diameter of 12 cm. The disk spins under a laser that reads encoded data. The first track to be r

serg [3582]

0.00066518 Nm

6 0

1 month ago

A 6.0-cm-diameter, 11-cm-long cylinder contains 100 mg of oxygen (O2) at a pressure less than 1 atm. The cap on one end of the c

Softa [3030]

Explanation:

Here is the provided information:

Mass of oxygen contained = 100 mg = $100 \times 10^{-3}$ g

Thus, the moles of oxygen can be calculated using the following formula:

n = $\frac{100 \times 10^{-3}}{32}$

= $3.125 \times 10^{-3}$ moles

Diameter of the cylinder = 6 cm = $6 \times 10^{-2}$ m

= 0.06 m

Next, we can determine the cross-sectional area (A) as follows:

A = $\pi \times \frac{(0.06)^{2}}{4}$

= $2.82 \times 10^{-3} m^{2}$

Length of the tube = 11 cm = 0.11 m

Thus, the volume (V) is given by $2.82 \times 10^{-3} \times 0.11$

= $3.11 \times 10^{-4} m^{3}$

For our calculations, we'll assume the internal pressure is P.

Moreover, $P_{atm}$ = 100 kPa = 100000 Pa,

The pressure difference amounts to 100000 - P

Thus, the force required to open is calculated as follows:

Force = Pressure difference × A

= $(100000 - P) \times 2.82 \times 10^{-3}$

We are provided with the information that the force equals 173 N.

Thus,

$(100000 - P) \times 2.82 \times 10^{-3}$ = 173

By solving, we find,

P = $3.8650 \times 10^{4} Pa$

= 38.65 kPa

Using the ideal gas equation, PV = nRT

Hence, we will input the values into the equation as follows:

PV = nRT

$38.65 \times 3.11 \times 10^{-4} = 3.125 \times 10^{-3} \times 8.314 \times T$

T = 462.66 K

Consequently, we can deduce that the gas temperature is 462.66 K.

6 0

1 month ago

Consider the vector b⃗ with magnitude 4.00 m at an angle 23.5∘ north of east. what is the x component bx of this vector? express

serg [3582]

By breaking down vector b into its x and y components, we form a right triangle where bx lies along the x-axis, by along the y-axis, and b represents the hypotenuse.
The x component bx equals the hypotenuse multiplied by the cosine of the angle between b and the x-axis, which is shown in $23.5 ^{\circ}$ :
$b_x = b \cos (23^{\circ})=(4.00 m)(\cos (23^{\circ}))=3.68 m$

6 0

3 months ago

A 10 kg migratory swan cruises at 20 m/s. A calculation that takes into ac- count the necessary forces shows that this motion re

Ostrovityanka [3204]

Response:

The total distance traveled by the swan amounts to

d = 864000 m

Portion of total mass that has been lost by it

$fraction = 0.0934$