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Valentin
4 days ago
13

Technician A says that some ABS wheel speed sensors are used as part of the tire pressure monitoring system (TPMS) . Technician

B says that the ABS is used as part of the hill assist system. Which technician is correct?
A. Technician A
B. Technician B
C. Technician A and B
D. Neither A nor B
Physics
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A student claims that earthquakes are more destructive than tsunamis. In one or two sentences, explain at least two reasons that
ValentinkaMS [3465]
An earthquake can impact individuals on land, causing greater destruction than a tsunami, which primarily affects those near the ocean.
8 0
2 months ago
Two charges q1 = 5 µC, q2 = -26 µC, are L = 19 cm apart. A third charge is to be placed on the line between the two charges. How
Keith_Richards [3271]
The electric force between two objects is expressed as being proportional to the product of their charges and inversely proportional to the square of the distance separating them. In this instance, the distance between the first two charges is 19 cm. We formulate the equation k q1 q3/ (x)^2 = k q2 q3/ (19-x)^2, where x denotes the separation between q1 and q3. The charge q3 cancels out, and q2 is used in absolute terms. The resulting value of x is 5.79 cm.
6 0
2 months ago
The height of a typical playground slide is about 6 ft and it rises at an angle of 30 ∘ above the horizontal.
Maru [3345]

Answer:

The coefficient of kinetic friction is found to be 0.432.

Explanation:

Comprehensive steps and derivations with necessary substitutions are detailed in the attached document.

6 0
3 months ago
Two very small 8.55-g spheres, 15.0 cm apart from center to center, are charged by adding equal numbers of electrons to each of
ValentinkaMS [3465]

Answer:

1.43 x 10¹⁷.

They will move away from each other.

Explanation:

The force acting on each charged sphere is determined as F = mass x acceleration

= 8.55 x 10⁻³ x 25 x 9.8

= 2.095 N

Assuming Q is the charge on each sphere

F = \frac{9\times10^9\times Q^2}{(15\times10^{-2})^2}

Using the values, 2.095 = \frac{9\times10^9\times Q^2}{(15\times10^{-2})^2}

We find that Q² = \frac{2.095\times(15)^2\times10^{-4}}{9\times10^9}

Thus, Q = 2.289 X 10⁻⁶

The quantity of electrons = Charge / charge of a single electron

= \frac{2.289\times10^{-6}}{1.6\times10^{-19}}

=1.43 x 10¹³.

They will accelerate away from each other.

4 0
2 months ago
Read 2 more answers
A communications satellite orbiting the earth has solar panels that completely absorb all sunlight incident upon them. The total
Ostrovityanka [3204]

Answer:

0.000047N

Explanation:

We know that

intensity (I) = P/ A

Where

P= power

A= Area

Thus, the power absorbed can be calculated as:

Power = Intensity x Area

This equals = 1.4 x 10^3 x(10)

Thus,

14000 Watts = 14 kWatt

However, the radiation pressure can be defined as

time-averaged intensity divided by the speed of light in a vacuum

So,

P = (1.4 x 1000)/c

Also,

F= P x A

Thus,

((1.4 x 1000)/(3 x10^8)) x 10

This results in

=0.000046666N

Rounded to two significant figures gives us

=0.000047 N

3 0
2 months ago
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