Yuto left his house at 10 a.M. To go for a bike ride. By the time Yuto's sister Riko left their house, Yuto was already 5.25 mil

Question

1 month ago

12

Yuto left his house at 10 a.M. To go for a bike ride. By the time Yuto's sister Riko left their house, Yuto was already 5.25 mil

es along the path they both took. If Yuto's average speed was 0.25 per minute and Riko's average speed was 0.35 per minute, over what time period in minutes,t, starting from when Riko left the house, will Riko be Behind her brother?

Mathematics

2 answers:

Leona [12.6K] · Answer 1 · 2026-02-21T18:39:44+03:00

Response:

The time range is;

from 10 am to 10:52 am

(At this moment, she will catch up at precisely 10:52 am, 30 seconds)

Detailed explanation:

We need to calculate the time it will take Riko to cover the same distance as Yuto.

In generic terms, at any time:

Speed = distance/time

Let x denote the time we want to find in minutes

At x minutes, Riko will have traveled 0.35 * x = 0.35x miles

At x minutes, Yuto will have covered a distance of 5.25 miles + 0.25 * x = (5.25 + 0.25x) miles

Note that at time x minutes, the distances traveled will be equal;

So,

0.35x = 5.25 + 0.25x

0.35x -0.25x = 5.25

0.1x = 5.25

x = 5.25/0.1

x = 52.5 minutes

During a span of 52.5 minutes, Riko will trail her brother;

Since Yuto left at 10 am, the time range extends from;

10 am to 10:52 am

Leona [12.6K] · Answer 2 · 2026-02-21T18:41:44+03:00

Response:

Sample Explanation: This solution illustrates that Riko will be trailing Yuto from the moment she departs the house, which is when t = 0, until she reaches Yuto after 52.5 minutes, corresponding to t = 52.5. Time cannot be less than zero as it represents a non-negative quantity.

Detailed explanation: Directly from Edg2020