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solniwko
11 days ago
8

Suppose you are designing an amplifier and loudspeaker system to use at a rock concert. You want to make it as loud as possible.

How can you design the system to maximize the volume? Explain your answer?
Hi, I’m very confused by this question. Is it referring to the right hand rule to predict where the force and current will face?


Thanks for helping!
Physics
1 answer:
Softa [2.9K]11 days ago
4 0
The response is outlined below. Audio power amplifiers are present in various sound systems, including those for sound reinforcement, public addresses, home audio, and musical instrument amplifiers like those for guitars. This component is the final electronic element in the audio playback chain before signals reach the loudspeaker. To achieve the loudest possible sound, it is essential to maximize output while maintaining high input and low output impedance.
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A small house was built on an island off a perfectly straight shoreline. The point B on the shoreline that is closest to the isl
Sav [3045]
Q should be positioned 4.8 miles east of point B. Explanation: From the diagram, we can define the construction cost as a function of angle θ (as illustrated). The underwater pipe length (marked in blue) equals 6/cos θ, while the land pipe length (marked in brown) is (8 - 6*tan θ). The total construction cost formula is: Construction Cost = (6/cos θ)(6000) + (8 - 6*tan θ)(3750). This formula is represented in terms of θ, which can vary from 0 degrees to 53.13 degrees according to the diagram. To find the angle θ that minimizes the construction cost, we differentiate the Construction Cost function with respect to θ and set it to zero. The derivative yields: -4500(5*sec θ – 8*tan θ)(sec θ) = 0, leading to θ = 38.68 degrees. By substituting θ, we can determine the distance of Q from B, which equals 6*tan θ. This calculates to a distance of 4.8 miles.
7 0
12 days ago
The drawing shows an adiabatically isolated cylinder that is divided initially into two identical parts by an adiabatic partitio
Yuliya22 [3228]

Answer:

the temperature on the left side is 1.48 times greater than that on the right

Explanation:

GIVEN DATA:

\gamma = 5/3

T1 = 525 K

T2 = 275 K

It is known that

P_1 = \frac{nRT_1}{v}

P_2 = \frac{nrT_2}{v}

n and v are constant on both sides. Therefore we have

\frac{P_1}{P_2} = \frac{T_1}{T_2} = \frac{525}{275} = \frac{21}{11}

P_1 = \frac{21}{11} P_2..............1

let the final pressure be P and the temperature T_1 {f} and T_2 {f}

P_1^{1-\gamma} T_1^{\gamma} = P^{1 - \gamma}T_1 {f}^{\gamma}

P_1^{-2/3} T_1^{5/3} = P^{-2/3} T_1 {f}^{5/3}..................2

similarly

P_2^{-2/3} T_2^{5/3} = P^{-2/3} T_2 {f}^{5/3}.............3

divide equation (2) by equation (3)

\frac{21}{11}^{-2/3} \frac{21}{11}^{5/3} = [\frac{T_1 {f}}{T_2 {f}}]^{5/3}

T_1 {f} = 1.48 T_2 {f}

thus, the left side temperature equals 1.48 times the right side temperature

6 0
26 days ago
A solar system may form from a spinning disk of material called a(n _____
serg [3469]
The correct term is accretion disk. This refers to a formation, typically a circumstellar disk, created by dispersed matter revolving around a large central body, which is usually a star. The gravitational pull causes the material in the disk to spiral inward towards the center.
4 0
5 days ago
Read 2 more answers
Ceres, Pluto, and Eris are all round in shape and classified as:_________ A) Leftover planetesimals that formed inside the frost
Keith_Richards [3146]

Answer

Ceres, Pluto, and Eris are categorized as DWARF PLANETS.

A) Remaining planetesimals formed within the frost line are referred to as ASTEROIDS.

B) METEORITES are fragments of asteroids that have landed on Earth.

C) COMETS are celestial objects that are often visible with their long tails.

D) COMETS are also planetesimals that were left over and originated in the region of the solar system dominated by the jovian planets.

E) Meteor showers are linked to debris from COMETS.

5 0
1 month ago
A bus slows down uniformly from 75.0 km/h to 0 km/h in 21 s. How far does it travel before stopping?
Yuliya22 [3228]

1 hour = 3,600 seconds
1 km = 1,000 meters

75 km/hour = (75,000/3,600) m/s = 20-5/6 m/s

The mean speed during the deceleration is

                                   (1/2)(20-5/6 + 0) = 10-5/12 m/s.

Traveling at this average speed for 21 seconds,
the bus covers

                        (10-5/12) × (21) = 218.75 meters.

7 0
1 month ago
Read 2 more answers
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