Object A and object B are initially uncharged and are separated by a distance of 1 meter. Suppose 10,000 electrons are removed f
1 answer:
Answer:
1
Explanation:
Let’s denote the charge magnitude for 10,000 electrons as .
When object A loses charge q, it results in a total charge of (since electrons are negatively charged, their loss turns A positively charged). On the other hand, B, which gains q, assumes a charge of
. They are initially 1 meter apart.
According to Coulomb’s law, the force acting between them is
When an additional 10,000 electrons are stripped from A, its charge becomes , while B’s charge becomes
. Now, they are 2 meters apart.
The force at this new distance is
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Result: -50.005 kJ
Details:
Provided Data
mass of the system = 10 kg
work done = 0.147 kJ/kg
Elevation change
initial speed
Final Speed
Specific internal Energy
according to the first Law of thermodynamics
where KE represents kinetic energy
PE indicates potential energy
U denotes internal Energy
Q = 1.47 + 3.375 - 4.850 - 50
Q = -50.005 kJ