Answer and Explanation: A. At temperature t = 32, the speed of sound, s = 1087.5. As the temperature increases by 1°F, speed increases by 1.2. Therefore, S = 1088.6 for T= 33°F. Given two equations: 1087.5 = k(32) + c and 1088.6 = k(33) + c. Subtracting yields (33-32)k = 1088.6 - 1087.5 leading to K = 1.1. Expression: S = kT + c; with 1087.5 = 32(1.1) + c, we find c = 1052.3. Hence, S = 1.1t + 1052.3. Rewriting as T = (s/1.1) - (1052.3/1.1) gives T = 0.90(s) - 956.3. This implies that the temperature rises by 0.90 for every 1 ft/s increase in sound speed.
I’ve provided the missing image. We can analyze this scenario by applying the principle of energy conservation. At point A, the car possesses both potential and kinetic energy. As it moves down the track, some initial energy is lost due to friction. Thus, as it approaches point B, we have a specific amount of energy remaining. According to the conservation of energy laws, this remaining energy at point B will equal the sum of its kinetic and potential energy.
