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Aloiza
3 months ago
9

15,000 blue trout were released into the Meherrin River for a scientific study. The function, f(x) = 15,000 (98)x , represents t

he number of blue trout after x years. In 5 years, what will happen to the population?
Mathematics
1 answer:
Inessa [12.5K]3 months ago
0 0

Answer:

I'm assuming you mean f(x)=15,000(9/8)^x. If so, the population rises by nearly 12,000 (specifically, 12030.4870605).

Step-by-step explanation:

Initial equation: f(x)=15,000(9/8)^x

We can simplify 9/8 to 1.125

You will need to calculate (9/8)^5 which equals 1.8020324707

Next, multiply 1.8020324707 by 15,000 for a result of 27030.4870605

Finally, subtract 15,000 from 27,030.4870605 to arrive at 12030.4870605, indicating an approximate increase of 12,000 in the population.

You might be interested in
If mJI = (3x+2)°, mHLK = (15x-36)°, and m∠HML = (8x-1)°, find mHLK
lawyer [12517]

Response:

The measure of mHLK is "(204)°".

Step-by-step breakdown:

Given values include:

mJI = (3x+2)°

mHLK = (15x-36)°

and,

m∠HML = (8x-1)°

then,

What is mHLK?

Now,

Utilizing the chord-chord angle formula, we find

mHMK=\frac{1}{2}(mJL+mHLK)

Inserting the known values into the equation gives us

⇒  (8x-1)=\frac{1}{2}(15x-36+3x+2)

By carrying out cross-multiplication, we arrive at

⇒  2(8x-1)=18x-34

⇒  16x-2=18x-34

By subtracting "18x" from both sides, we obtain

⇒  16x-2-18x=18x-34-18x

⇒  -2x-2=-34

Upon adding "2" to both sides, we end up with

⇒  -2x=-34+2

⇒  -2x=-32

⇒  x=\frac{32}{2}

⇒  x=16

By substituting the value of "x" into mHLK = (15x-36)°, we calculate

⇒ (15x-36)° = (15×16-36)°

⇒                = (240-36)°

⇒                = (204)°

Thus, mHLK = (204)°

4 0
3 months ago
A bag contains chips of which 27.5 percent are blue. A random sample of 5 chips will be selected one at a time and with replacem
lawyer [12517]

Answer:

\mu _{\hat{p}}= 0.275\\\\ \sigma_{\hat{p}}=0.1997

Step-by-step explanation:

It is known that the mean and standard deviation of the sampling distribution of the sample proportion(\hat{p}) are represented as follows:-

\mu _{\hat{p}}=p\\\\ \sigma_{\hat{p}}=\sqrt{\dfrac{p(1-p)}{n}}

, where p= Population proportion and n = sample size.

Let p denote the proportion of blue chips.

According to the information provided, we have

p= 0.275

n= 5

Thus, the mean and standard deviation of the sampling distribution of the sample proportion of blue chips for samples of size 5 will be:

\mu _{\hat{p}}= 0.275\\\\ \sigma_{\hat{p}}=\sqrt{\dfrac{ 0.275(1- 0.275)}{5}}\\\\=0.19968725547\approx0.1997

Therefore, you will have the mean and standard deviation for the sample proportion of blue chips for samples of size 5:

\mu _{\hat{p}}= 0.275\\\\ \sigma_{\hat{p}}=0.1997

6 0
2 months ago
By law, all businesses outside the Parkville city limits must fence their lots. How many inches of fence will be needed to fence
AnnZ [12381]
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8 0
1 month ago
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