Response:
V1 = 20.3L
Clarification:
P2 = 811.4Pa
V2 = 25.6L
P1 = 1023.6Pa
V1 =?
To answer this query, we will utilize Boyle's law, which states that the volume of a gas at constant temperature is inversely related to its pressure.
In mathematical terms,
V = k / P, where k = PV
The relationship can be defined as P1 × V1 = P2 × V2 = P3 × V3 =......=Pn × Vn
This simplifies to P1 × V1 = P2 × V2
Let’s rearrange for V1
V1 = (P2 × V2) / P1
Substituting values gives
V1 = (811.4 × 25.6) / 1023.6Pa
So, V1 = 20771.84 / 1023.6
This results in V1 = 20.29L, rounded to 20.3L
Answer:
CaS, CaBr₂, VBr₅, and V₂S₅.
Explanation:
- The ionic compound must exhibit neutrality; its total charge should equal zero.
- A binary ionic compound is formed from two distinct ions.
Ca²⁺ combines with either Br⁻ or S²⁻ to create binary ionic compounds.
- CaS is created when Ca²⁺ pairs with S²⁻ resulting in the neutral binary ionic compound CaS.
- CaBr₂ results from the combination of one mole of Ca²⁺ with two moles of Br⁻ to form the neutral binary ionic compound CaBr₂.
V⁵⁺ can also unite with either Br⁻ or S²⁻ to produce binary ionic compounds.
- V₂S₅ is formed when two moles of V⁵⁺ bond with five moles of S²⁻ yielding the neutral binary ionic compound V₂S₅.
- VBr₅ is produced by combining one mole of V⁵⁺ with five moles of Br⁻ to form the neutral binary ionic compound VBr₅.
Thus, the empirical formulas for four binary ionic compounds that may be produced are: CaS, CaBr₂, VBr₅, and V₂S₅.
The answer is D. Aluminium Oxide 0.10, Magnesium Oxide 0.50. Firstly, for sodium hydroxide, we can calculate the number of moles using the formula moles = concentration × volume, leading to 0.2 moles from 100 cm³ at 2 moldm-3. Since 2 moles of NaOH yield 1 mole of Al2O3, this means 0.2 moles of NaOH produces 0.1 moles of Al2O3. For hydrochloric acid, moles can similarly be determined, leading to 1.6 moles from 800 cm³ at 2 moldm-3. Considering that 1 mole of Al2O3 reacts with 6 moles of HCl, 0.1 moles of Al2O3 will consume 0.6 moles of HCl. Post-reaction, we have 1 mole of HCl remaining, which will further react with magnesium oxide, thereby yielding 0.5 moles of MgO.
The correct answers are B and D. Explanation: Given the information presented, we have absorption bands at 3300 cm-1 and 2200 cm-1, indicating the presence of an alkyne functional group. Furthermore, the hydrogenation of the unknown compound utilizes two moles of hydrogen, which correlates with the two pi bonds found in the alkyne group. Hence, we can eliminate choices "a" and "e." Since hydrogenation yields 2-methylhexane, option c is also dismissed, given that the methyl group attaches at carbon 3. Therefore, structures b and d remain viable.
Answer:
Explanation:
We have:
V₁ = 18.5 L
T₁ = 18.5° C = 273 + 18.5 = 291.5 K
V₂ = 19.8 L
T₂ =?
Pressure remains constant
Applying the ideal gas law
