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Ludmilka
10 days ago
7

A student wants to prepare a 1.0-liter solution of a specific Molarity. The student determines that the mass of the solute needs

to be 30. grams. What is the proper procedure to follow?
(1) Add 30. g of solute to 1.0 L of solvent.
(2) Add 30. g of solute to 970. mL of solvent to make 1.0 L of solution.
(3) Add 1000. g of solvent to 30. g of solute.
(4) Add enough solvent to 30. g of solute to make 1.0 L of solution.
Chemistry
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The accurate statements are presented below: 1) It requires minimal energy to break O-P bonds in ATP. 2) The OH-P bond formed is a weak bond. 3) Breaking the O-P bond releases energy that was stored in it.
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2 months ago
Which of the following statements describe physical properties and which describe chemical properties? (a) Iron has a tendency t
Anarel [2989]

Answer:

Explanation:

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b) Precipitation in industrialized areas often has an acidic nature -- this is also a chemical property due to its interaction with bases or metals.

c) Hemoglobin is red in color -- this is a physical property since it doesn't entail any chemical reactions.

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8 0
3 months ago
15 g of gold and 25 g of silver are mixed to form a single-phase ideal solid solution.
Anarel [2989]
1. The total moles of the solution is 0.3079193 mol. 2. The mole fraction for gold is 0.2473212, and for silver, it is 0.7526787. 3. The molar entropy of mixing for gold is 2.87285 j/K, while for silver, it is 1.77804 j/K. 4. The total entropy of mixing sums to 4.65089 j/K. 5. Molar free energy amounts to -2325.445 kJ. 6. Chemical potential for silver is -1750.31129 j/mol and for gold, it is -575.13185 j/mol. To elaborate: (1) The molar mass of silver stands at 107.8682 g/mol, and gold's at 196.96657 g/mol. Hence, calculating moles leads to mass/molar mass for silver: 25 g/107.8682 g/mol = 0.2317643 mol and for gold: 15 g/196.96657 g/mol = 0.076155 mol, resulting in a total of 0.30791193 mol. (2) For the mole fractions, silver's fraction is 0.2317643/0.3079193 = 0.7526787, and for gold, it's 0.076155/0.3079193 = 0.2473212. (3) To find molar entropy mixing ∆Sm, we use the formula ∆Sm = -R * Xi * ln(Xi) where R = 8.3144598. For silver, substituting gives us 1.77804 j/K, while for gold, we get 2.87285 j/K. (4) Overall entropy of mixing totals 4.65089 j/K thus calculated. (5) The Gibbs free energy at 500 °C can be derived through G = H - TS, accounting to H = 0 (as T is 500 + 273 = 773 K and S is 4.65089), resulting in G equating to -3595.138 kJ. (6) The chemical potentials calculated derive from multiplying the Gibbs free energy by their mole fractions.
8 0
1 month ago
Which of the following statements are TRUE concerning this laboratory exercise - The systematic identification of an organic com
KiRa [2933]
True; True; False; True; True. Explanation: Organic compounds can exist in pure form, but they are typically found in mixtures, such as in petroleum, which implies that the compound one obtains could be impure. Organic compounds can exist in three states: solid, liquid, or gas. The state depends on the molecular forces and the molar mass involved. For instance, at room temperature, gasoline is a liquid, natural gas is a gas, and glucose is a solid. The fundamental characteristic of organic compounds is that they contain carbon (C) and hydrogen (H), while other elements like oxygen (O), nitrogen (N), halogens, and sulfur (S) may or may not be part of their structure. Because carbon can form chains, millions of organic compounds are known. Spectroscopic methods can provide information such as composition, molar mass, and diffraction patterns, which can assist in identifying certain chemical properties and may require additional identification tests.
5 0
1 month ago
The density of a 50% solution of naoh is 1.525 g/ml. what volume of a solution that is 50% by weight naoh is required to make 0.
eduard [2782]
We assume that the stated 50% is measured by volume. Molarity defines the concentration in terms of moles of solute per volume of solution.

      To find the moles of NaOH, use: (0.1 moles / L)(0.4 L)
                      n = 0.04 moles of NaOH

Assuming we start with 1 mL of 50% NaOH solution, 
  
                        (1 mL solution)(1.525 g/mL)(0.50) = 0.7625 g
Then, the number of moles calculates as follows,[
                  0.7625 g NaOH x (1 mol / 40 g) = 0.01906 moles of NaOH

                The volume of solution required can be determined by:(0.04 moles of NaOH)(1 mL solution / 0.01906 moles of NaOH)
                 
                 Thus, the needed volume comes out to be 2.09 mL

Answer: 2.09 mL
3 0
2 months ago
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