Answer:
Explanation:
Chlorine has an electron configuration of 2, 8, 7
Within the n = 3 shell, it has 7 electrons consisting of 2 in the s subshell and 5 in the p subshell. However, one of the p electrons shifts to the d orbital, altering the electronic configuration to be as follows
= 7
These orbitals such as sp³d hybridize, creating 7 degenerate orbitals where two orbitals are filled with electron pairs and three remain singly occupied by electrons (unpaired electrons).
To determine the length of each side,
employ the distance formula represented by the equation:
Distance = ((x2-x1)^2+(y2-y1)^2)^0.5
Calculating
<span>AB = 8 units BC = 6 units AC = 10 units
</span><span>MN =8units NO = 6 units MO = 10 units
</span><span>XY = 6.32 units YZ = 6.32 units XZ = 8.94 units
</span>JK = 4.47 units KL = 4.47 units JL = 6 units
1 The correct response is option b) triangles ABC and MNO are Congruent. <span>These triangles, ABC and MNO, have congruent side lengths.
</span>2 The answer is option c) rotation.
There is a rotation of 90º around the origin for triangles ABC and MNO, where B=N,
B=N
C----------O
A----------M
Response: Water molecules migrate from the dilute to the concentrated solution
Clarification:
During osmosis, when a solution is separated by a semipermeable membrane, the solvent (commonly water) moves from the less concentrated solution, regarding solute content, through the semipermeable membrane towards the solution with a higher concentration to balance the concentration levels between the two solutions.
Thus, in this scenario, water molecules flow from the 0.4M sugar solution to the 0.7M sugar solution through the semipermeable membrane.
x is greater than or equal to 56Step-by-step explanation: He requires at least 56 additional cans. Hence, x should be a minimum of 56.
Response:
H₂SO₄
Clarification:
Given a compound consisting of 0.475 g H, 7.557 g S, and 15.107 g O, we must compute the empirical formula by following specific steps.
Step 1: Compute the total mass of the compound
Total mass = mass H + mass S + mass O = 0.475 g + 7.557 g + 15.107 g
Total mass = 23.139 g
Step 2: Determine the percentage composition.
H: (0.475g/23.139g) × 100% = 2.05%
S: (7.557g/23.139g) × 100% = 32.66%
O: (15.107g/23.139g) × 100% = 65.29%
Step 3: Divide each percentage by the element's atomic mass
H: 2.05/1.01 = 2.03
S: 32.66/32.07 = 1.018
O: 65.29/16.00 = 4.081
Step 4: Normalize all values by the smallest one
H: 2.03/1.018 ≈ 2
S: 1.018/1.018 = 1
O: 4.081/1.018 ≈ 4
Thus, the empirical formula for the compound is H₂SO₄.
